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raketka [301]
3 years ago
14

Help MEEEEEE PLEASEEEEEEE

Mathematics
2 answers:
Anton [14]3 years ago
4 0

Answer:

4 1/3 hours

Step-by-step explanation:

Since he will have completed 7 hours AFTER 2 2/3 more hours, he has completed 7- 2 2/3 = 4 1/3 hours so far

nasty-shy [4]3 years ago
4 0
The answer would be 4 1/3 hours
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3 years ago
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The sum of two numbers is 19 . When the second number is subtracted from the first​ number, the difference is 17 . Find the two
zhenek [66]

Answer:

19 and 2

Step-by-step explanation:

Let x represent the first number and y represents second number

x + y = 19

x - y = 17 add two equations up

2x = 36 divide both sides by 2

x = 19 and since the difference is 17 the other number is 2

4 0
2 years ago
James invests $5,000 at an annual rate of 8% simple interest for 7 years. How much is in the account
borishaifa [10]

Answer:

$8,569.12

Step-by-step explanation:

6 0
3 years ago
D^2(y)/(dx^2)-16*k*y=9.6e^(4x) + 30e^x
MA_775_DIABLO [31]
The solution depends on the value of k. To make things simple, assume k>0. The homogeneous part of the equation is

\dfrac{\mathrm d^2y}{\mathrm dx^2}-16ky=0

and has characteristic equation

r^2-16k=0\implies r=\pm4\sqrt k

which admits the characteristic solution y_c=C_1e^{-4\sqrt kx}+C_2e^{4\sqrt kx}.

For the solution to the nonhomogeneous equation, a reasonable guess for the particular solution might be y_p=ae^{4x}+be^x. Then

\dfrac{\mathrm d^2y_p}{\mathrm dx^2}=16ae^{4x}+be^x

So you have

16ae^{4x}+be^x-16k(ae^{4x}+be^x)=9.6e^{4x}+30e^x
(16a-16ka)e^{4x}+(b-16kb)e^x=9.6e^{4x}+30e^x

This means

16a(1-k)=9.6\implies a=\dfrac3{5(1-k)}
b(1-16k)=30\implies b=\dfrac{30}{1-16k}

and so the general solution would be

y=C_1e^{-4\sqrt kx}+C_2e^{4\sqrt kx}+\dfrac3{5(1-k)}e^{4x}+\dfrac{30}{1-16k}e^x
8 0
3 years ago
Complete the the ratio to convert the units of measure from ounces to grams to ounces ?​
otez555 [7]

Answer:

84 and 5

3x28=84

140 divided by 28=5

7 0
3 years ago
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