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bonufazy [111]
2 years ago
10

Extra Practice: Identify the point used in

Mathematics
1 answer:
expeople1 [14]2 years ago
4 0

Answer:

  (a)  (4, 5)

Step-by-step explanation:

The point-slope form of the equation for a line is ...

  y -k = m(x -h) . . . . . . where m is the slope and (h, k) is the point

Comparing this to

 y -5 = 1/2(x -4)

we see that k=5, m=1/2, h=4. Then the point is ...

  (h, k) = (4, 5)

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Answer:

Length: x + 5

Step-by-step explanation:

x² + 8x + 15 = length × width

x² + 8x + 15

x² + 5x + 3x + 15

x(x + 5) + 3(x + 5)

(x + 5)(x + 3)

Width: (x + 3)

Length: (x + 5)

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3 years ago
Smallest to largest. Here are four decimal numbers: 0.9, 0.5, 0.8, 0.1
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0.1,0.5,0.8,0.9

Step-by-step explanation:

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2 years ago
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Moe is 12 years older than Barney .three years ago ,moe was five times as old as Barney .how old is Barney now
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The answer is 7 years old.
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Find the product of all real values of r for which 1/2x=r-x/7
Dahasolnce [82]

Answer:

r = \±\sqrt{14

Product = -14

Step-by-step explanation:

Given

\frac{1}{2x} = \frac{r - x}{7}

Required

Find all product of real values that satisfy the equation

\frac{1}{2x} = \frac{r - x}{7}

Cross multiply:

2x(r - x) = 7 * 1

2xr - 2x^2 = 7

Subtract 7 from both sides

2xr - 2x^2 -7= 7 -7

2xr - 2x^2 -7= 0

Reorder

- 2x^2+ 2xr  -7= 0

Multiply through by -1

2x^2 - 2xr +7= 0

The above represents a quadratic equation and as such could take either of the following conditions.

(1) No real roots:

This possibility does not apply in this case as such, would not be considered.

(2) One real root

This is true if

b^2 - 4ac = 0

For a quadratic equation

ax^2 + bx + c = 0

By comparison with 2x^2 - 2xr +7= 0

a = 2

b = -2r

c =7

Substitute these values in b^2 - 4ac = 0

(-2r)^2 - 4 * 2 * 7 = 0

4r^2 - 56 = 0

Add 56 to both sides

4r^2 - 56 + 56= 0 + 56

4r^2 = 56

Divide through by 4

r^2 = 14

Take square roots

\sqrt{r^2} = \±\sqrt{14

r = \±\sqrt{14

Hence, the possible values of r are:

\sqrt{14 or -\sqrt{14

and the product is:

Product = \sqrt{14} * -\sqrt{14}

Product = -14

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3 years ago
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