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alukav5142 [94]
2 years ago
15

Let () = sin( 3 ). a. Find ′ ()

Mathematics
1 answer:
Radda [10]2 years ago
7 0

Answer:

.052

Step-by-step explanation:

sin(3) = .052

() = sin(3)

() = .052

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How many coupons did they send to the existing members?
Dvinal [7]
Hello!

If we try and use 50 coupons for the existing members, and the problem states that they gave FOUR times more than that to potential members, and 250 being our max, then:

250-50= 200

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So that means that they gave 50 coupons to existing members.
5 0
3 years ago
Read 2 more answers
What is the slope of the line that passes through the points (4, 2) and (−16,−10)? Write your answer in simplest form
Rufina [12.5K]

Step-by-step explanation:

slope = y2 - y1

__________

x2 - x1

slope = (-10 -2) / (-16 - 4)

slope = -12/-20

slope = 3/5

7 0
3 years ago
I will mark brainiest , I'm giving out my points so hurry!<br> Would you rather
Fed [463]

Answer:

Cube 1

Step-by-step explanation:

Volume of cube 1

V = 25*25*25 = 15625


Volume of 2 cubes

V = 24*24*24 = 13824

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The total volume is greater for the 1 cube

7 0
3 years ago
Question 2
Scrat [10]

Answer:

The inverse of the function is;

x = (y + 2)/3

Step-by-step explanation:

Here in this question, we shall be calculating the inverse of a function.

The function is;

y = 3x - 2

Firstly, let w = x;

y = 3w -2

y + 2 = 3w

w = (y + 2)/3

Now replace w by x

x = (y + 2)/3

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7 0
3 years ago
Yuri thinks that 3/4 is a root of the following function.
sineoko [7]

Given:

The polynomial function is

q(x)=6x^3+19x^2-15x-28

Yuri thinks that \dfrac{3}{4} is a root of the given function.

To find:

Why \dfrac{3}{4} cannot be a root?

Solution:

We have,

q(x)=6x^3+19x^2-15x-28

If \dfrac{3}{4} is a root, then the value of the function at \dfrac{3}{4} is 0.

Putting x=\dfrac{3}{4} in the given function, we get

q(\dfrac{3}{4})=6(\dfrac{3}{4})^3+19(\dfrac{3}{4})^2-15(\dfrac{3}{4})-28

q(\dfrac{3}{4})=6(\dfrac{27}{64})+19(\dfrac{9}{16})-\dfrac{45}{4}-28

q(\dfrac{3}{4})=3(\dfrac{27}{32})+\dfrac{171}{16}-\dfrac{45}{4}-28

q(\dfrac{3}{4})=\dfrac{81}{32}+\dfrac{171}{16}-\dfrac{45}{4}-28

Taking LCM, we get

q(\dfrac{3}{4})=\dfrac{81+342-360-896}{32}

q(\dfrac{3}{4})=\dfrac{-833}{32}\neq 0

Since the value of the function at \dfrac{3}{4} is not equal to 0, therefore, \dfrac{3}{4} is not a root of the given function.

4 0
3 years ago
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