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3 years ago

5

Solve for v Simply as much as possible 9v=16+v

2 answers:

qaws [65]3 years ago

8 0

Answer:

v=2

Step-by-step explanation:

9v=16+v

9v-v=16

8v=16

v=16/8

v=2

Andreas93 [3]3 years ago

7 0

V=2 Because V-9=8 8/16=2 Simple

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(NEED HELP ASAP!!) You are saving for a skateboard. Your aunt gives you $45 to start, and you save $3 each

nekit [7.7K]

Answer:

$63

Step-by-step explanation:

You have the constant, $45. You then receive $3 each week. This can be written at $45 + $3w, where w is the number of weeks. So in this case, we need to find out how much money you will have after 6 weeks. We just need to plug in 6 weeks into the equation. The new equation will now be $45 + $3(6).

3 times 6 is $18.

$45 + $18 will give you a final answer of $63.

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2 years ago

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D) 35m is the answer

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2 years ago

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An object is dropped from a bridge and allowed to freefall to the ground. The height of the object over time can be modeled usin

kkurt [141]

Answer:

<em>t = 3 seconds</em>

Step-by-step explanation:

We have the equation, as a function of time, that describes the height of the object that is dropped from the bridge.

The equation is:

$h (t) = 144 - 16t ^ 2$

Where t is the time in seconds and h is the height in feet.

To know how long it takes the object to fall to the ground we do h (t) = 0 and solve for t.

So:

$0 = 144 - 16t ^ 2\\\\16t ^ 2 = 144\\\\t ^ 2 = \frac{144}{16}\\\\t ^ 2 = 9\\\\t_1 = 3\\t_2 = -3$

We take the positive solution.

Therefore the object takes 3 seconds to reach the ground

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2 years ago

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How do you solve 5x +x

34kurt

If you are just simplifying it it would be 6x because it's 5x plus one more x but if you are trying to find x then I have no idea

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2 years ago

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What degree of rotation is represented on this matrix

Korvikt [17]

Answer:

Option B is correct

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Step-by-step explanation:

A rotation matrix is a matrix that is used to perform a rotation in Euclidean space.

To find the degree of rotation using a standard rotation matrix i.e,

$R = \begin{bmatrix}\cos \theta & -\sin \theta \\ \sin \theta & \cos \theta \end{bmatrix}$

Given the matrix: $\begin{bmatrix}0 & 1 \\ -1 & 0\end{bmatrix}$

Now, equate the given matrix with standard matrix we have;

$\begin{bmatrix}\cos \theta & -\sin \theta \\ \sin \theta & \cos \theta \end{bmatrix}$ = $\begin{bmatrix}0 & 1 \\ -1 & 0\end{bmatrix}$

On comparing we get;

$\cos \theta = 0$ and $-\sin \theta =1$

As,we know:

$\cos \theta = \cos(-\theta)$

$\sin(-\theta) = -\sin \theta$

$\cos \theta = \cos(90^{\circ}) = \cos( -90^{\circ})$

we get;

$\theta = -90^{\circ}$

and

$\sin \theta =- \sin (90^{\circ}) = \sin ( -90^{\circ})$

we get;

$\theta = -90^{\circ}$

Therefore, the degree of rotation is, $-90^{\circ}$

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3 years ago