#This is a way without a loop
friends = list(map(str,input("Enter Names: ").split()))
print(sorted(friends))
#This is a way with a loop (for&&while)
friends = list(map(str,input("Enter Names: ").split()))
cool = True
while cool:
cool = False
for i in range(len(friends)-1):
if friends[i] > friends[i+1]:
coo = friends[i]
friends[i] = friends[i+1]
friends[i+1] = coo
cool = True
print(friends)
Answer:
C. Use the SOAP API to maintain the related SObject_share records
Explanation:
In order to ensure that Universal Containers have complete control over the system, the company needs to use certain requirements. This is to ensure that non-authorized persons do not have any access to the information. Based on the information provided in the question, the correct option is option C.
Answer:
A wave that has been digitized can be played back as a wave over and over, and it will be the same every time. For that reason, digital signals are a very reliable way to record information—as long as the numbers in the digital signal don’t change, the information can be reproduced exactly over and over again.
Explanation:
Answer:
zero ( 0) times.
Explanation:
In the code;
i = 2
while ( i > 2){
i = floor( i/2 );
z = z + 1;
}
the variable " i " is assigned the integer " 2 ", then the while statement loops with a condition of a greater " i " value and divides the value by two for every loop.
But in this case, the while statement is not executed as the value of " i " which is 2 is not greater than but equal to two.