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OLEGan [10]
3 years ago
14

What do computer programs generally try to solve and how? A) Computer programs generally try to solve a well-defined problem usi

ng a well-defined algorithm B) Computer programs try to solve poorly-defined problems using well-defined algorithms C) Computer programs try to solve well-defined problems using poorly-defined algorithms D) Computer programs try to solve math problems using only plain English
Computers and Technology
1 answer:
otez555 [7]3 years ago
5 0

Explanation:

<em>A</em><em>)</em><em> </em><em>computer</em><em> </em><em>programs</em><em> </em><em>generally</em><em> </em><em>try</em><em> </em><em>to</em><em> </em><em>solve</em><em> </em><em>hard</em><em> </em><em>problems</em><em> </em><em>in</em><em> </em><em>a</em><em> </em><em>few</em><em> </em><em>seconds</em><em> </em><em>and</em><em> </em><em>makes</em><em> </em><em>us</em><em> </em><em>easy</em><em> </em><em>to</em><em> </em><em>learn</em>

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What are options in the Advanced tab in the Share Workbook dialog box? Check all that apply.
viva [34]

All options in the Advanced tab in the Share Workbook dialog box.

  • Don’t keep change history
  • Show comments made by all users
  • Update changes when file is saved
  • Track changes for certain amount of days
  • Allow changes by more than one user at a time
  • Automatically update changes in certain time periods

<u>Explanation:</u>

In shared workbook in advanced tab it has following options. Based on end user selection changes are applied on shares workbook.

1. Either keep the history for certain period or don’t keep the history on shared workbook.

2. On share work Save changes on period schedule (automatically update) or just see other user changes.

3. Before changes are made for share workbook either prompt for save option or last modified saved.

4.  Printer review and filter setting for personal view.

8 0
3 years ago
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Delicious77 [7]
The correct answer is D
6 0
3 years ago
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Is anyone else excited for sephiroth (I think I spelt it wrong) in smash. And if you arn't are you excited for christmas
Fed [463]

Answer: idek what that is but okay ;v;

7 0
3 years ago
Consider the following methods:
elena55 [62]
3. 8.1  
Looking at the functions "average", and "mystery" it's pretty obvious that "average" returns a double precision average of the value of an integer array. The function "mystery" returns an array of integers with each value in the array being the length of the string in the array of strings passed to "mystery" in the same ordinal position.  
The main body of the code initializes an array of strings and then passes that array to "mystery" who's output is then passed into the function "average". Since the lengths of the words passed to "mystery" is 7, 5, 6, 10, 10, 8, 13, 6, 8, 8, the sum will be 81, so the average will be 81/10 = 8.1 which matches option "3".
4 0
3 years ago
Write a program that reads in an integer value for n and then sums the integers from n to 2 * n if n is nonnegative, or from 2 *
devlian [24]

Answer:

Following are the program in c++

First code when using for loop

#include<iostream> // header file  

using namespace std; // namespace

int main() // main method

{

int n, i, sum1 = 0; // variable declaration

cout<<"Enter the number: "; // taking the value of n  

cin>>n;

if(n > 0) // check if n is nonnegative

{

for(i=n; i<=(2*n); i++)

{

sum1+= i;

}

}

else //  check if n  is negative

{

for(i=(2*n); i<=n; i++)

{

sum1+= i;

}

}

cout<<"The sum is:"<<sum1;

return 0;

Output

Enter the number: 1

The sum is:3

second code when using while loop

#include<iostream> // header file  

using namespace std; // namespace

int main() // main method

{

int n, i, sum1 = 0; // variable declaration

cout<<"Enter the number: "; // taking the value of n  

cin>>n;

if(n > 0) // check if n is nonnegative

{

int i=n;  

while(i<=(2*n))

{

sum1+= i;

i++;

}

}

else //  check if n  is negative

{

int i=n;  

while(i<=(2*n))

{

sum1+= i;

i++;

}

}

cout<<"The sum is:"<<sum1;

return 0;

}

Output

Enter the number: 1

The sum is:3

Explanation:

Here we making 2 program by using different loops but using same logic

Taking a user input in "n" variable.

if n is nonnegative then we iterate the loops  n to 2 * n and storing the sum in "sum1" variable.

Otherwise iterate a loop  2 * n to n and storing the sum in "sum1" variable.  Finally display  sum1 variable .

4 0
3 years ago
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