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2 years ago

Amy's home is 1.8 km from the shop.

Mathematics

1 answer:

anastassius [24]2 years ago

5 0

Answer:

18 km/ h

sorry it didn't help

but hope it helps

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Consider the equation |1/4+12|=x/2.Without calculating, how do you know x=-16 is an extraneous solution?

telo118 [61]

Without calculating, you can immediately see the absolute value sign, which implies that the final result (x) should be positive, not negative.

5 0

3 years ago

Please help will give brainliest it’s for a test<br><br> Round 29.20 to 30 <br> Show work please

djverab [1.8K]

Answer:

you cant round that to 30

Step-by-step explanation

29.20

29.2 2 is less than 5

so you cant round you can only round if the .tens place is 5 or more

4 0

3 years ago

A used car has a value of 15,250 when it’s purchased in 2012. The value of the car decreases at a rate of 7.5% per year

kotegsom [21]

p=15250

r=7.5/100=0.075

y = 15250*(1 - 0.075)^x

after 8 years it would be

x = 8

y = 15250*(1 - 0.075)^8

y = $8,173.42

after 8 years the value of the car is going to be $8,173.42

8 0

3 years ago

How do I find the missing side lengths? Someone please help!!!

adell [148]

45°-45°-90°
Hope I could help!

3 0

3 years ago

The article "Occurrence and Distribution of Ammonium in Iowa Groundwater" (K. Schilling, Water Environment Research, 2002:177–18

Papessa [141]

Answer: 95% confidence interval for the difference between the proportions would be (1.31, 1.39).

Step-by-step explanation:

Since we have given that

Number of alluvial wells = 349

Number of quaternary wells = 143

Number of alluvial wells that had concentrations above 0.1 = 182

Number of quaternary wells that had concentrations above 0.1 = 112

Average of alluvial wells = 0.27

Standard deviation = 0.4

Average of quaternary wells = 1.62

Standard deviation =1.70

So, 95% confidence interval gives

alpha = 5% level of significance.

$\dfrac{\alpha}{2}=2.5\%\\\\z_{\frac{\alpha}{2}}=1.96$

So, 95% confidence interval becomes,

$(1.62-0.27)\pm 1.96\sqrt{\dfrac{0.4^2}{349}+\dfrac{1.7^2}{143}}\\\\=1.35\pm 1.96\times 0.020\\\\=(1.35-0.040,1.35+0.040)\\\\=(1.31,1.39)$

Hence, 95% confidence interval for the difference between the proportions would be (1.31, 1.39).

6 0

3 years ago