Answer:
$284.99 should go to Mr. Aceves’ class, $174.41 should go to Mrs. Baca’s class, and $140.60 should go to Mr. Canyon’s class.
Step-by-step explanation:
Firstly, to calculate the portions each class should have, we should find the proportion each class takes up.
Hence, let's say A represents Mr. Aceves' class, B represents Mrs. Baca's class, and C represents Mr. Canyon's class.
The total number of box tops collected would be 3760 + 2301 + 1855 = 7916 box tops.
Therefore, the total proportions would be:
A = 
B = 
C = 
Hence, we can finally multiply these proportions with the total prize to find the appropriate division:
Mr. Aceves' class gets
.
Mrs. Baca's class gets
.
And Mr. Canyon's class gets
.
Finally, $284.99 should go to Mr. Aceves’ class, $174.41 should go to Mrs. Baca’s class, and $140.60 should go to Mr. Canyon’s class.
Hope this helped!
Answer:
Largest Median: Same
Largest Range: Castro
Largest IQR: Castro
Step-by-step explanation:
With a box-and-whisker plot, the box represents the upper and lower quartiles, the vertical line inside the box represents the median, and the lines on either side of the box show the high and low of the range.
Largest Median: Medians are the same because the verticle line inside the boxes is at 7 for both
Largest Range: Ms Castro's Class- the lines on either side of the box for Ms Castro go from 1-10 while the other class only goes from 4-10.
Largest IQR (interquartile range) Ms. Castro's class: their IQR goes from 5-8 while the other class only goes from 6-8
Answer:
<h2>
45</h2>
Step-by-step explanation:

So, if the common ratio is 5 the next term is always 5 times the previous term.
<h3>9·5 = 45</h3>
3 m/h=0.05m/m
.05•5=0.25 m/h I believe?