Answer:
that shall answer 15 < 4x on a number line
Step-by-step explanation:
view image for more clarity
Answer: 
Step-by-step explanation:
Given
Marcos purchased a sailboat for 
Each year the boat will decrease in value by 
After 1 year it is

after another year it becomes

After
years it is


The answer would most commonly be C only because a square is 360 degrees and the surface area would be a 6th of that which is 60 then i multiplied it by 4 because of the four corners signaling the height and or length of the 2D figure square which gives me C.
(-1.2,-2.0) and (1.9,2.2) are the best approximations of the solutions to this system.
Option B
<u>Step-by-step explanation:</u>
Here, we have a graph of two functions from which we need to find the approximate value of common solutions. Let's find this:
First look at where we have intersection points, In first quadrant & in third quadrant.
<u>At first quadrant:</u>
Draw perpendicular lines from x-axis & y-axis from this point . After doing this we can clearly see that the perpendicular lines cut x-axis at x=1.9 and y-axis at y=2.2. So, one point is (1.9,2.2)
<u>At Third quadrant:</u>
Draw perpendicular lines from x-axis & y-axis from this point. After doing this we can clearly see that the perpendicular lines cut x-axis at x=-1.2 and y-axis at y= -2.0. So, other point is (-1.2,-2.0).