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Lyrx [107]
2 years ago
6

The length of a rectangle is 8 cm more then 4 times the with. If the perimeter of the rectangle is 46 cm, what are the dimension

s
Mathematics
2 answers:
avanturin [10]2 years ago
5 0

Answer:

15

Step-by-step explanation:

let the breadth be x

let the length be x+8

perimeter of rectangle=2 (length +breadth)

so, 2 (x+x+8)=44cm

=2 (2x+8)=44

=4x + 16=44

=4x= 44-16

=4x= 28

=x = 28÷4

=x= 7

therefore,

breadth is 7 (x)

length is 7+8 (x+8)

=15

skad [1K]2 years ago
3 0
3, 20


Mark brainliest please


Hope this helps you
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What is the median of the data set?<br><br><br><br> 9<br> 8.5<br> 8<br> 10
Allushta [10]

Answer:

8.5

Step-by-step explanation:

When you write out the data set, it looks like this:

5, 8, 8, 8, 8, 9, 9, 9, 10, 10

The median means the exact middle of the data set. In this case, it falls between the 8 and the 9, so the middle would be 8.5, so that's the median of the set. I hope this helps :)

6 0
3 years ago
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One urn contains one blue ball (labeled B1) and three red balls (labeled R1, R2, and R3). A second urn contains two red balls (R
marusya05 [52]

Answer:

(a) See attachment for tree diagram

(b) 24 possible outcomes

Step-by-step explanation:

Given

Urn\ 1 = \{B_1, R_1, R_2, R_3\}

Urn\ 2 = \{R_4, R_5, B_2, B_3\}

Solving (a): A possibility tree

If urn 1 is selected, the following selection exists:

B_1 \to [R_1, R_2, R_3]; R_1 \to [B_1, R_2, R_3]; R_2 \to [B_1, R_1, R_3]; R_3 \to [B_1, R_1, R_2]

If urn 2 is selected, the following selection exists:

B_2 \to [B_3, R_4, R_5]; B_3 \to [B_2, R_4, R_5]; R_4 \to [B_2, B_3, R_5]; R_5 \to [B_2, B_3, R_4]

<em>See attachment for possibility tree</em>

Solving (b): The total number of outcome

<u>For urn 1</u>

There are 4 balls in urn 1

n = \{B_1,R_1,R_2,R_3\}

Each of the balls has 3 subsets. i.e.

B_1 \to [R_1, R_2, R_3]; R_1 \to [B_1, R_2, R_3]; R_2 \to [B_1, R_1, R_3]; R_3 \to [B_1, R_1, R_2]

So, the selection is:

Urn\ 1 = 4 * 3

Urn\ 1 = 12

<u>For urn 2</u>

There are 4 balls in urn 2

n = \{B_2,B_3,R_4,R_5\}

Each of the balls has 3 subsets. i.e.

B_2 \to [B_3, R_4, R_5]; B_3 \to [B_2, R_4, R_5]; R_4 \to [B_2, B_3, R_5]; R_5 \to [B_2, B_3, R_4]

So, the selection is:

Urn\ 2 = 4 * 3

Urn\ 2 = 12

Total number of outcomes is:

Total = Urn\ 1 + Urn\ 2

Total = 12 + 12

Total = 24

5 0
3 years ago
1 point
Alex

Answer:

Step-by-step explanation:

tan49=h/17

h=17tan49

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5 0
3 years ago
My question is what is the answer to 2y = x + 3 <br> x = y
Brilliant_brown [7]

Answer:

(0,0)

Step-by-step explanation:

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Find the value of f(-8).
fredd [130]

Answer:

-8f

Step-by-step explanation:

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