All categories

3 years ago

DESCRIBE A RULE YOU COULD USE TO FIND

Mathematics

2 answers:

kherson [118]3 years ago

8 0

Answer:

Blue Tiles: 1n(figure number)=t(number of tiles)

White Tiles: 8n=t

For example:

8(2)=16

so this means this problem would be 8(∞) because its pattern can never be broken unless it is disrupted

Hope this helps :)

Edit: Tysm for brainly!

Ivan3 years ago

7 0

Answer:

Multiply by 8

You might be interested in

Simplify by combining like terms: -3 + 6x - 18 - 22x

alekssr [168]

Answer: -16x-21

Explanation: 6x + (-22x)=-16x
-18+(-3)=-21

8 0

3 years ago

Read 2 more answers

How do you do this!???

german

Answer:

x=2

Step-by-step explanation:

assuming this shape is euclidean (don't pay attention to this just some extra info, assume that all triangles on a sheet of paper have angles summing to 180)

The sum of all angles in a triangle is 180, so

90+60+15x=180

150+15x=180

15x=30

x=2

5 0

3 years ago

The endpoint of gh are g (10,1) and h (3,5). What is the midpoint of gh?

sergij07 [2.7K]

Answer:

(6.5,3)

please see the attached picture for full solution...

Hope it helps...

Good luck on your assignment.....

8 0

3 years ago

Read 2 more answers

Find the missing exponent. 2^{3}\cdot 2^{?}=2^{10}2

guapka [62]

Answer:

Step-by-step explanation:

2^3 • 2^7 = 2^10

When multiplying exponents, the exponents add up together. In other words, just subtract 10-3 = 7 that would be your missing exponent!

Hope this helps, good luck!

5 0

3 years ago

Read 2 more answers

At the start of the year, 15 chameleons were introduced into a zoo. The population of chameleons is expected to grow at a rate o

bearhunter [10]

Answer:

option-B

Step-by-step explanation:

We are given

At the start of the year, 15 chameleons were introduced into a zoo

so, $P_0=15$

The population of chameleons is expected to grow at a rate of 41.42% every year

so, r=0.4142

and x represents the number of years since the chameleons were introduced into the zoo

now, we can set equation to find total population

and we get

$P(x)=P_0(1+r)^x$

now, we can plug values

$P(x)=15(1+0.4142)^x$

$P(x)=15(1.4142)^x$

Average rate of change between 2 years and 4 years:

we can use formula

$A_1=\frac{P(4)-P(2)}{4-2}$

now, we can plug values

$A_1=\frac{15(1.4142)^{4}-15(1.4142)^{2}}{4-2}$

$A_1=14.99914$

Average rate of change between 4 years and 6 years:

we can use formula

$A_2=\frac{P(6)-P(4)}{6-4}$

now, we can plug values

$A_2=\frac{15(1.4142)^{6}-15(1.4142)^{4}}{6-4}$

$A_2=29.99770$

Average rate of change between 6 years and 8 years:

we can use formula

$A_3=\frac{P(8)-P(6)}{8-6}$

now, we can plug values

$A_3=\frac{15(1.4142)^{8}-15(1.4142)^{6}}{8-6}$

$A_3=59.99425$

now, we will check each options

option-A:

we can see that

$A_3-A_2=30$

So, this is FALSE

option-B:

$A_1=\frac{1}{2}A_2$

So, this is TRUE

option-C:

This is FALSE

option-D:

we got

$A_1=\frac{1}{2}A_2$

so, this is FALSE

5 0

3 years ago