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vaieri [72.5K]
2 years ago
5

-33=3(x-9) Solve for x

Mathematics
2 answers:
White raven [17]2 years ago
7 0

Answer:

x=-2

Step-by-step explanation:

-33/3=-11

-11+9=-2

CHECKING

-33=3(-2-9)

-33=3•-11

-33= -33

Orlov [11]2 years ago
5 0

Answer:

x=-2

Step-by-step explanation:

\sf -33=3(x-9)

\sf 3\left(x-9\right)=-33

\sf \frac{3\left(x-9\right)}{3}=\frac{-33}{3}

\sf x-9=-11

\sf x-9+9=-11+9

\sf x=-2

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Solve the Quetion fine with the variable equals to make it true<br> (x+3)(x-5)=0 show your work
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Step-by-step explanation:

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3 years ago
The function f(x)f(x) is a quartic function and the zeros of f(x)f(x) are -6−6, -5−5, -2−2 and 11. Assume the leading coefficien
Luden [163]
<h2>Answer: </h2>

\boxed{f(x) = 11x^4 + 22x^3 - 1001x^2 - 5632x - 7260}

<h2>Explanation: </h2>

A quartic function is a function given by the the following equation in standard form:

f(x)=a_{4}x^4+a_{3}x^3+a_{2}x^2+a_{1}x+a_{0} \\ \\ \\ Where: \\ \\ a_{4},a_{3},a_{2},a_{1},a_{0} \ \text{are constant} \\ \\ \text{and} \ a_{4} \ \text{is the leading coefficient}

From the statement we must assume the leading coefficient of f(x) is 11, so:

a_{4}=11

The zeros are:

x=-6 \\ \\ x=-5 \\ \\ x=-2 \\ \\ x=11

So, we can write:

f(x)=11(x-(-6))(x-(-5))(x-(-2))(x-11) \\ \\ \\ So: \\ \\ \mathrm{Rule}:-\left(-a\right)=a \\ \\ \\ Then: \\ \\ f(x)=11\left(x+6\right)\left(x+5\right)\left(x+2\right)\left(x-11\right)

Expand:\left(x+6\right)\left(x+5\right):\ x^2+11x+30: \ \text{Distributive Property} \\ \\ \\ Then: \\ \\ f(x)=11\left(x^2+11x+30\right)\left(x+2\right)\left(x-11\right) \\ \\ \\ Expand:\left(x^2+11x+30\right)\left(x+2\right):\ x^3+13x^2+52x+60:  \ \text{Distributive Property} \\ \\ \\ Then: \\ \\ f(x)=11\left(x^3+13x^2+52x+60\right)\left(x-11\right)

Expand: \left(x^3+13x^2+52x+60\right)\left(x-11\right):\ x^4+2x^3-91x^2-512x-660 \\  (Distributive \ property)

Finally:

f(x) = 11(x^4 + 2x^3 - 91x^2 - 512x - 660) \\ \\ \boxed{f(x) = 11x^4 + 22x^3 - 1001x^2 - 5632x - 7260}

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irga5000 [103]

The set that is more variable is the daily temperature as they won't be clustered but rather spread out.

<h3>How to know the set that's more variable?</h3>

The mean of the temperature will be:

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Answer:

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