<span>o,t,t,f,f,s,S,E,N,T,E,T </span>
<span>It's the first letter of all the numbers starting with one, two, three, four,... </span>
<span>The second pattern I might guess would be move the O back two spaces then move one space back, then repeat. </span>
<span>JKLMNO, JKLOMN, JKOLMN, OJKLMN, JKLMON, JKOLMN, ... </span>
<span>The second one I'm not sure about because there are only three starting terms to work with. It's hard to see the real pattern with that little to work with. </span>
<span>Hope this helps. </span>
The answer its D. i just learn that in class.
F'(x)=(2/3(x^2-2x-1)^-1/3 )*(2x-2) chain rule here
f'(0) is equals to substitute x with 0. Which gives
f'(0)= (2/3(-1)^-1/3)*(-2)
Plug in the calculator, and your answer is ready
