Assume that
a and b = the two legs of the right triangle.
c = the hypotenuse.
The area of the right triangle is 750 yd², therefore
(1/2)*a*b = 750
ab = 1500 (1)
The perimeter is 150yd, therefore
a + b + c = 150 (2)
Let the side fenced with wood be a, at $5/yd. Sides b and c are fenced with steel at $10/y. The total cost is $1200, therefore
5a + 10b + 10c = 1200
or
a + 2b + 2c = 240 (3)
From (2), obtain
c = 150 - a - b (4)
Substitute (4) into (3)
a + 2b + 2(150 - a - b) = 240
-a + 300 = 240
a = 60
From (1), obtain
60b = 1500
b = 25
From (4), obtain
c = 150 - 60 - 25 = 65
Answer:
A. The length of the leg fenced with wood is 60 yd.
B. The length of the leg fenced with steel is 25 yd.
Answer:
120-(30+48)= 42
Step-by-step explanation:
<h3>
Answer: f( h(x) ) = 2x - 4</h3>
Work Shown:
f(x) = x - 7
f( h(x) ) = h(x) - 7
f( h(x) ) = 2x+3 - 7
f( h(x) ) = 2x - 4
Explanation:
In the second step, I replaced every x with h(x). In the next step, I replaced the h(x) on the right hand side with 2x+3. From there I combined like terms.
Answer:
-2
Step-by-step explanation:
(-3x/2) - 3 = 3
add 3 to both sides
(-3x/2) = 3
multiply both sides by 2
-3x = 6
divide both sides by -3
x= -2
