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3 years ago

What is the solution to the linear equation?

Mathematics

2 answers:

GalinKa [24]3 years ago

8 0

Answer:

-10 -2d+7=8-10-3d

-2d + 7 =8 -3d

-2d + 7 =3d = 8

-2d + 3d = 8-7

d=8-7

d=1

Vadim26 [7]3 years ago

8 0

Answer:

$d = 1$

Step-by-step explanation:

Step 1: Combine like terms

$d - 10 - 2d + 7 = 8 + d - 10 - 3d$

$(d - 2d) + (-10 + 7) = (8 - 10) + (d - 3d)$

$(-d) + (-3) = (-2) + (-2d)$

Step 2: Add 2d to both sides

$-d + 2d - 3 = -2 - 2d + 2d$

$d - 3 = -2$

Step 3: Add 3 to both sides

$d - 3 + 3 = -2 + 3$

$d = 1$

Answer: $d = 1$

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mina [271]

Answer:

$\frac{-6+\sqrt{78} }{6}$ and $\frac{-6-\sqrt{78} }{6}$

Step-by-step explanation:

We are asked that what are the zeros of the quadratic function f(x) = 6x² +12x -7.

So, we have to find the roots of the equation, f(x) = 6x² +12x -7 =0 ...... (1)

Since the quadratic function can not be factorized, so we have to apply Sridhar Acharya's formula.

This formula gives if, ax² +bx +c =0, the the two roots of the equation are

$\frac{-b+\sqrt{b^{2}-4ac } }{2a} , \frac{-b-\sqrt{b^{2}-4ac } }{2a}$

Therefore, in our case 'a' being 6, 'b' being 12 and 'c' being -7, the two roots of the equation (1) will be

$\frac{-12+\sqrt{12^{2}-4*6*(-7) } }{2*6}, \frac{-12-\sqrt{12^{2}-4*6*(-7) } }{2*6}$

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(Answer)

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