Answer:
Step-by-step explanation:
ignore the "at the instant the man is 30 feet away" part, set it as X and the man's shadow as Y.
Similar triangles so we can do 
.
Solve for it we get 44y = 6x
Differentiate relative to time t, we get 44y' = 6x'.
change in x (x') is equal to 5. And we get the answer y' = 
.
the ft/sec is the rate of which the length of the shadow is changing. add 5 to it for the rate of the tip of his shadow moving away from the tower.
The value of three in 6,300 is 3,000 because it is in the thousands place. The three in 530 is in the hundreds place making the value of three 300. Hope that this helps you :D
Imagine A'V' is part of the dilated figure, and AV is part of the original figure.
A'V' = 3.2
AV = 3.2 + 4.8 = 8
A'V'/AV = 3.2/8 = 2/5
Answer: First choice, 2/5.
I think you're asking if it's possible to have a cube root, fifth root, 7th root, etc of a number as a solution to f(x). The answer is yes it's possible.
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Example:
f(x) = x^3 - 29
This function has one real-number root of ![x = \sqrt[3]{29}](https://tex.z-dn.net/?f=x%20%3D%20%5Csqrt%5B3%5D%7B29%7D)
(cube root of 29) and the other two roots are complex or imaginary roots.
