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Fofino [41]
3 years ago
9

How much would $200 invested at 7% interest compounded annually be

Mathematics
1 answer:
Inessa05 [86]3 years ago
5 0

Answer:

$280.51

Step-by-step explanation:

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523 x = 523 x = last one
Sphinxa [80]

Answer:

X has an infinite number of solutions

or

0 = 0

Step-by-step explanation:

<em>Hey there!</em>

Given,

523x = 523x

Simplify

523x = 523x

-523x to both sides

0 = 0

<u>So x has an infinite number of solutions.</u>

<em>Hope this helps :)</em>

5 0
3 years ago
Read 2 more answers
Let L: R2 --&gt; R2 be a linear operator.If L((1,2)T) = (-2,3)Tand L((1,-1)T) = (5,2)TFind the value of L((7,5)T
devlian [24]

Answer: L((7,5)T)=(7, 18)T

Step-by-step explanation:

The step by step explanation is given in picture.

3 0
3 years ago
What is the square root of 365
valina [46]
19.1 should be your answer
7 0
4 years ago
Read 2 more answers
What is the equation of a line that is perpendicular to y=4x-5 and passes through (-4,6)
lozanna [386]

Answer:

y=-1/4x+5

Step-by-step explanation:

perpendicular lines have slopes that multiply to -1.

Our given line:

y=4x-5

the slope (m) in it is 4. To find the slope of the perpendicular line:

4m=-1

divide by 4

m=-1/4

the slope of the new line is -1/4

here's our equation so far:

y=-1/4x+b

Since the line will pass through the point (-4,6) we can use it to solve for b (y intercept)

so substitute (-4,6) into the equation

6=-1/4(-4)+b

6=1+b

5=b

the y intercept is 5

so our equation is:

y=-1/4x+5

hope this helps! :D

4 0
3 years ago
Solve the Equation p+5/8=15/16?
Sphinxa [80]
So the first thing you want to do when faced with two fractions with different denominators (when subtracting or adding) is to make the denominators the same. So for this equation they would turn out to be p+10/16=15/16 (because 16 is the lowest common denominator, 8 times two) so then you want to subtract 10/16 from 15/16 to isolate the variable (p) which would get: 
p=5/16
This is the final answer because it cannot be simplified.
Hope this helps!
6 0
4 years ago
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