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velikii [3]
2 years ago
14

1. change .84 to a fraction, reduced

Mathematics
1 answer:
Inga [223]2 years ago
5 0

Answer:

1. 21/25

2. 72

3. -4

4. Typo?

2I+2w= 33

21+2w=34

5. Dont understand this question withought context

Step-by-step explanation:

1. 84/4 and 100/4 is 21/25

2. 3(6)(-4) miltiplication

3. worry about parenthesis first, a positive plus a negatative goes to minus so 6-4 then multiply 2 times -2 and get -4

4.

2I+2w is 2(10)+2(6.5)

21+2w is 21+2(6.5)

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Answer:

Option B and C

Step-by-step explanation:

5^{-6} x 5^{4} / 5^{-4}

5^{-2} / 5^{-4}  =  5^{2}

 5^{2} = 25

Option B : 25

and C :  5^{2}

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6 0
2 years ago
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34. Find the mean for the following data X F 10 3 12 5 14 4 16 5 18 3​
Neko [114]
Answer- 9 you have to add all the numbers together then divide but the amount of numbers there are
5 0
3 years ago
What are the steps to solving this?
Archy [21]

Answer:

64 cubic metres

Step-by-step explanation:

The triangular pyramid volume formula resembles the volume formula for any other pyramid or cone:

V = A * H / 3

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H is the height from the base to the point

In other words: the volume of a triangular pyramid is one-third of the product of the base area and the pyramid's height.

8 x 6 / 2 to find area of base = 24

x 8 = 192

192 / 3 = 64

Hope this makes sense. If you would like, I can l1nk to a very useful website, or I can explain it further.

- profparis

5 0
2 years ago
What is 1.2 simplified
natali 33 [55]

Answer:

it is 1 2/10 but simplified to 1 1/5

Step-by-step explanation:

5 0
2 years ago
How do you simplify <img src="https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%7B2%7D%20%2B%5Csqrt%7B6%7D%20%7D%7B%5Csqrt%7B8%7D%20%2B%
blondinia [14]

The trick is to exploit the difference of squares formula,

a^2-b^2=(a-b)(a+b)

Set a = √8 and b = √6, so that a + b is the expression in the denominator. Multiply by its conjugate a - b:

(\sqrt8+\sqrt6)(\sqrt8-\sqrt6)=(\sqrt8)^2-(\sqrt6)^2=8-6=2

Whatever you do to the denominator, you have to do to the numerator too. So

\dfrac{\sqrt2+\sqrt6}{\sqrt8+\sqrt6}=\dfrac{(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)}{(\sqrt8+\sqrt6)(\sqrt8-\sqrt6)}=\dfrac{(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)}2

Expand the numerator:

(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)=\sqrt{2\cdot8}+\sqrt{6\cdot8}-\sqrt{2\cdot6}-(\sqrt6)^2

(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)=\sqrt{16}+\sqrt{48}-\sqrt{12}-6

(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)=4+\sqrt{48}-\sqrt{12}-6

(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)=-2+\sqrt{12}(\sqrt4-1)

(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)=-2+\sqrt{12}(2-1)

(\sqrt2+\sqrt6)(\sqrt8-\sqrt6}=-2-\sqrt{12}

So we have

\dfrac{\sqrt2+\sqrt6}{\sqrt8+\sqrt6}=-\dfrac{2+\sqrt{12}}2

But √12 = √(3•4) = 2√3, so

\dfrac{\sqrt2+\sqrt6}{\sqrt8+\sqrt6}=-\dfrac{2+2\sqrt3}2=\boxed{-1-\sqrt3}

7 0
2 years ago
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