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3 years ago

Which is the most appropriate to describe a quantity decreasing at a steady rate

Mathematics

1 answer:

Elis [28]3 years ago

7 0

Which is the most appropriate to describe a quantity decreasing at a steady rate?

With a linear equation.

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HELP PLEASE

Gala2k [10]

Answer:

3-11n>21-5n

Step-by-step explanation:

It seems right, so hopefully it is.

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2 years ago

Find the area and circumference of a circle with a radius of 18 in. Round

Andre45 [30]

ANSWER:-

where is the given part

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3 years ago

Tyler needs to complete this table for his consumer science class. He knows that 1 tablespoon contains 3 teaspoons and that 1 cu

aalyn [17]

Answer:

1 pint=32 1 quart=64 1 gallon=256

Step-by-step explanation:

5 0

3 years ago

A large tank is filled to capacity with 300 gallons of pure water. brine containing 5 pounds of salt per gallon is pumped into t

Licemer1 [7]

If $A(t)$ is the amount of salt in the tank at time $t$ , then the rate at which this amount changes over time is given by the ODE

$A'(t)=\dfrac{3\text{ gal}}{1\text{ min}}\cdot\dfrac{5\text{ lb}}{1\text{ gal}}-\dfrac{3\text{ gal}}{1\text{ min}}\cdot\dfrac{A(t)\text{ lb}}{300+(3-3)t\text{ gal}}$

$A'(t)+\dfrac1{100}A(t)=15$

We're told that the tank initially starts with no salt in the water, so $A(0)=0$ .

Multiply both sides by an integrating factor, $e^{t/100}$ :

$e^{t/100}A'(t)+\dfrac1{100}e^{t/100}A(t)=15e^{t/100}$
$\left(e^{t/100}A(t)\right)'=15e^{t/100}$
$e^{t/100}A(t)=1500e^{t/100}+C$
$A(t)=1500+Ce^{-t/100}$

Since $A(0)=0$ , we have

$0=1500+C\implies C=-1500$

so that the amount of salt in the tank over time is given by

$A(t)=1500(1-e^{-t/100})$

After 10 minutes, the amount of salt in the tank is

$A(10)=1500(1-e^{-1/10})\approx142.74\text{ lb}$

8 0

3 years ago

A book that you want is 15$. You have a coupon for 5% off. How much will you pay?

Rzqust [24]

Answer:

$14.25

Step-by-step explanation:

15×5% = .75

15-.75 = 14.25

3 0

2 years ago