How is the weight moving during the time period X=4 and X = 5?
1 answer:
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Hello!
(7x²y³)(3x⁵y⁸)
Multiply by ADDING exponents with the same base:
(7 * 3) (x² * x⁵) (y³ * y⁸)
21 * x² ⁺ ⁵ * y³ ⁺ ⁸
Simplify:
21 * x⁷ * y¹¹
21x⁷y¹¹
Answer:
n=3.8416≅4
So Minimum Sample Size is 4
Step-by-step explanation:
In order to find the minimum sample size, the formula we use will be:
Where:
n is sample size
Z is the distribution
S is the standard deviation
E is the Margin of error
S=3 ,E=3
For Z:
Alpha=1-0.95=0.05
Alpha/2=0.025=2.5%
From Cumulative Standard Distribution Table:
Z at Alpha/2 = 1.960
n=3.8416≅4
So Minimum Sample Size is 4