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solmaris [256]
3 years ago
15

Find the greatest common factor of the following monomials: 15r25 48353

Mathematics
2 answers:
Yuri [45]3 years ago
6 0
475r35 is what I think the answer is
Cerrena [4.2K]3 years ago
3 0

Answer:

475r35

Step-by-step explanation:

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What is the actual distance around the garden?It took Clare 30 minutes to walk around the garden at a constant speed
konstantin123 [22]

Answer:

f she walks for 30 minutes, that means she was traveling at about 280 feet per minute (8,400÷30=280), or about 16,800 feet per hour

Step-by-step explanation:

8 0
3 years ago
A bank offers auto loans to qualified customers. The amount of the loans are normally distributed and have a known population st
vlabodo [156]

Answer: 1.467

Step-by-step explanation:

Formula of Margin of Error for (n<30):-

E=t_{\alpha/2}\dfrac{\sigma}{\sqrt{n}}

Given : Sample size : n= 22

Level of confidence = 0.90

Significance level : \alpha=1-0.90=0.10

By using the t-distribution table ,

Critical value : t_{n-1, \alpha/2}=t_{21,0.05}= 1.720743

Standard deviation: \sigma=4

Then, we have

E=(1.720743)\dfrac{4}{\sqrt{22}}=1.46745456106\approx1.467

Hence, the margin of error for the confidence interval for the population mean with a 90% confidence level =1.467

5 0
3 years ago
Read 2 more answers
A fossil was analyzed and determined to have a carbon-14 level that is 80 % that of living organisms. the half-life of c-14 is 5
liq [111]

Answer:

The fossil is 1860 years old.

Step-by-step explanation:

The equation for the amount of fossil has the following format:

Q(t) = Q(0)e^{rt}

In which Q(t) is the amount after t years, Q(0) is the initial amount and r is the rate of change.

Half-life of c-14 is 5730 years.

This means that Q(5730) = 0.5Q(0)

So

Q(t) = Q(0)e^{rt}

0.5Q(0) = Q(0)e^{5730r}

e^{5730r} = 0.5

\ln{e^{5730r}} = \ln{0.5}

5730r = \ln{0.5}

r = \frac{\ln{0.5}}{5730}

r = -0.00012

So

Q(t) = Q(0)e^{-0.00012t}

How old is the fossil?

This is t for which

Q(t) = 0.8Q(0)

So

Q(t) = Q(0)e^{-0.00012t}

0.8Q(0) = Q(0)e^{-0.00012t}

e^{-0.00012t} = 0.8

\ln{e^{-0.00012t}} = \ln{0.8}

-0.00012t = \ln{0.8}

t = -\frac{\ln{0.8}}{-0.00012}

t = 1860

The fossil is 1860 years old.

4 0
3 years ago
PLEASE HELP PLEASE PLEASE
Alecsey [184]
<h2>Coordinate Pairs</h2>

Coordinate pairs are organized like (x,y).

  • x tells us the location of the point in relation to the x-axis, the axis that is horizontal.
  • y tells us the location of the point in relation to the y-axis, the axis that is vertical.

To determine a coordinate pair, we can determine each coordinate individually, then put them together.

<h2>Solving the Question</h2>

Notice how the red point sits on the very edge of the graph.

When we look at the x-axis, we can see that it occurs at the number 0 on the x-axis. In other words, the red point occurs when x=0.

When we look at the y-axis, we can see that it lines up with the number 2. In other words, the red point occurs when y=2.

Therefore, when we put the two coordinates together like (x,y), we get (0,2).

<h2>Answer</h2>

(0,2)

4 0
2 years ago
Simplify the expression:<br> 10q–3q+2q2+3
saw5 [17]
If the 2q is raised to the second power the answer is 2q^2+7q+3
4 0
2 years ago
Read 2 more answers
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