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jonny [76]
3 years ago
13

Help no troll answer plz

Mathematics
1 answer:
stealth61 [152]3 years ago
7 0

Answer:

Step-by-step explanation:

<u><em>Q 4.</em></u> (25m + 25m) ÷ 25 sec. = <em>2 m/sec.</em>

<u><em>Q 5.</em></u> This question belongs to Physics and not Mathematics!!!

Wavelength (lambda) = Velocity (v) ÷ Frequency ( sec^{-1} or Hz )

f = v / (lambda)

f = 3 / 2 = <em>1.5 (Hz)</em>

<u><em>Q 6.</em></u> 0.060 ÷ 2 = <em>0.030 m</em>

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if -2 is a root of the equation 3x2 +7x + p = 0, find the values of k for which the roots of the equation x2 + k(4x + k - 1) + p
goblinko [34]

Answer:

first 0ne

Step-by-step explanation:

4 0
3 years ago
Please answer!!!! Will mark Brainlyest
Brilliant_brown [7]

Answer:

The coefficient is 3.

Step-by-step explanation:

Perimeter of a triangle= a+b+c

x + 10 + x + 15 + x + 12

<u>3</u>x + 37

7 0
3 years ago
Write an equation in slope-intercept form of the line passing through (0, 3) and (2, -1).
zheka24 [161]

Hi there!  

»»————- ★ ————-««

I believe your answer is:  

y = -2x + 3

»»————- ★ ————-««  

Here’s why:  

⸻⸻⸻⸻

\boxed{\text{Slope-Intercept Form Is:}}\\\\y=mx + b\\---------------\\\boxed{\text{Key:}}\\\\m - slope\\b - y-intercept\\---------------\\\boxed{\text{\underline{Known Information:}}}\\\\\rightarrow \text{We are given the points: } (0,3) \text{ and } (2, -1)\\---------------\\\boxed

\boxed{\text{\underline{Y-Intercept:}}}\\\\\rightarrow \text{Since the line passes at point (0, 3), the y-intercept would be 3.}\\---------------\\\boxed{\text{\underline{Slope:}}}\\\\\rightarrow m =\frac{rise}{run}=\frac{y_2-y_1}{x_2-x_1} \\\\\rightarrow m =  \frac{-1-3}{2-0}=\frac{-4}{2}=\boxed{-2}\\\\\text{The slope is: } \boxed{-2}\\---------------

\boxed{\text{\underline{Equation:}}}\\\\\text{Our equation should be:}\\\\y = -2x + 3

⸻⸻⸻⸻

»»————- ★ ————-««  

Hope this helps you. I apologize if it’s incorrect.

5 0
3 years ago
Write an equation of the line that passed through (7,10) and is perpendicular to the line y=1/2x-9
zmey [24]

Answer:

The perpendicular line passing through the point (7,10) is

2 x+y-24=0

Step-by-step explanation:

<u>Step :1 </u>

<u>perpendicular condition :-</u>

The condition of perpendicular lines are m_{1} m_{2} = -1

The given line is y= \frac{1}{2}x-9and given point is (7,10)

the standard form of straight line is y=m x+c

The given line is y= \frac{1}{2}x-9

here m = \frac{1}{2}

now by using perpendicular condition solving the slope of perpendicular line is m_{1} m_{2} =-1

     m_{2} = - \frac{1}{m_{1} }

     m_{2} = \frac{-1}{\frac{1}{2} }

    m_{2} = -2

<u>straight line equation</u>

<u>Step 2 :-</u>

The equation of the straight line having slope m=-2 and passing through the point (7,10) is

y-y_{1} = m (x-x_{1})

There fore the equation of perpendicular straight line is

y-10 = -2 (x-7)

y-10 = -2 x+14

<u>Final answer </u>

The equation of perpendicular straight line is

2 x+y-24=0

<u></u>

8 0
3 years ago
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