Question

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Answer 1

Answer:

$\boxed{2\pm \frac{\sqrt{2}}{2}}$

Step-by-step explanation:

$2x^2-8x=-7$

$\sf Add \ 7 \ on \ both \ sides}.$

$2x^2-8x+7=-7+7$

$2x^2-8x+7=0$

$ax^2 +bx+c=0$

$\sf Apply \ quadratic \ formula.$

$a=2 \ \ \ b=-8 \ \ \ c = 7$

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

$x=\frac{-(-8)\pm\sqrt{(-8)^2-4(2)(7)}}{2(2)}$

$x=\frac{8\pm\sqrt{64-56}}{4}$

$x=\frac{8\pm\sqrt{8}}{4}$

$x=\frac{8\pm2\sqrt{2}}{4}$

$x=2\pm \frac{\sqrt{2}}{2}$