change the mixed numbers into improper fractions
4 1/2 = (2*4 +1)/2= 9/2
1 1/2 = (2*1+1)/2 = 3/2
9/2 divided by 3/2
9/2 * 2/3 = 18/6 =3
She can schedule 3 lessons per night
Substitute the values of the radius <span>(<span><span>r=3</span>),</span></span><span> the </span>height <span>(<span><span>h=11</span>),</span></span><span> and an approximation of </span>Pi <span>(<span>3.14)</span></span><span> into the </span>formula<span> to find the </span>volume<span> of the </span>cone<span>.
</span><span>V≈+<span>1/3</span>⋅3.14⋅<span>3^2</span>⋅11
</span><span>Simplify.
</span>Write 3.14<span> as a </span>fraction<span> with </span>denominator <span>1.</span><span>
</span><span>V≈+<span>1/3</span>⋅<span>3.14/1</span></span> <span>
</span>Combine <span>1/3</span><span> and </span><span>3.14/1</span><span> to get </span><span><span>3.14/3</span>.</span><span>
</span><span>V≈+<span>3.14/3</span></span><span>
</span>
Replace back in to larger expression<span>.
</span><span>V≈+<span>3.14/3</span>⋅<span>3^2</span>⋅11</span><span>
</span>
Divide 3.14<span> by </span>3<span> to get </span><span>1.04666667.
</span><span>V≈+1.04666667⋅<span>3^2</span>⋅11
</span>Raise 3<span> to the </span>power<span> of </span>2<span> to get </span><span>9.
</span><span>V≈+1.04666667⋅9⋅11
</span>Multiply 1.04666667<span> by </span>9<span> to get </span><span>9.42.
</span><span>V≈+9.42⋅11
</span>Multiply 9.42<span> by </span>11<span> to get </span><span>103.62.
</span><span>V≈+103.62
</span>Remove trailing zeros<span> from </span><span>103.62.
</span><span>V≈+103.62</span><span>f<span>t^3
Volume:
</span></span>V≈+103.62ft^3
Answer:
u = 22
Step-by-step explanation:
The triangles are congruent by SAS, so HI = JI.
2u = u +22
u = 22 . . . . . . . subtract u from both sides
Answer: Cyclic quadrilateral
Step-by-step explanation:
Since angles OMB and ONC are right angles, it follows that AMO and ANO are also right angles. Thus, there is a pair of opposite angles that are supplementary, and thus AMON is a cyclic quadrilateral.
