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brilliants [131]
3 years ago
14

If y=12x-7 were changed to y=12x+1, how would the graph of the new function compare to the original?

Mathematics
2 answers:
ivanzaharov [21]3 years ago
6 0
A) y=12x-7        and    b) y=12x+1.

1st, these 2 functions are parallel since they have the same slope (m=12)
2nd in a) For x = 0, y = -7, meaning the line intersects with y-axis at y=-7
3rd in b) For x = 0 , y = +1, meaning the line intersects with y-axis at y=1

Likurg_2 [28]3 years ago
4 0
When we have the equation of a line y=mx+b, the "b" value tells you how high or low the line is. your b value when from -7 to 1. with the -7, each point on the line would have been lowered 7 units from its original position. changing the -7 to a 1 will raise the line y=12x+1 8 units, because 1-(-7) = 1+7 = 8.
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Viktor [21]
This is actually a very simple problem when you understand how to do it.

First, I would add the 12 to both sides. 
Equation would now look like this x/6=24 
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3 years ago
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3 years ago
What is the equation of the line that is parallel to the line y − 1 = 4(x + 3) and passes through the point (4, 32)
Finger [1]
<span>y − 1 = 4(x + 3) 
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y = 4x + 13, slope = 4
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</span><span>passes through the point (4, 32)
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equation
y = 4x + 16
4 0
3 years ago
Read 2 more answers
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irakobra [83]

Answer:

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3 0
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