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krek1111 [17]
3 years ago
6

Solve the system of linear equations by adding or subtracting.

Mathematics
1 answer:
Sav [38]3 years ago
7 0

Answer:

add bc when you subtract it will mess up your answer bc were literally doing the same thing in school at least i think adding right

Step-by-step explanation:

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Calculate the number of acres required to produce 1,000 gallons of oil in one year from microalgae and soybeans. Which one (micr
Inessa05 [86]

Answer:

microalgae required less space.

Step-by-step explanation:

Amount of oil to be produced = 1,000 gallons

Now,

We know

10,000 gallons of oil is extracted from the miroalgae per acre per year

and,

From soyabeans the oil extracted = 50 gallons per acre per year

therefore,

To produce 1,000 gallons number of acres required by microalgae

= [ Amount of oil to be produced ] ÷ [ oil extracted per acre from microalgae]

= 1,000 ÷ 10,000

= 0.1 acres

similarly

To produce 1,000 gallons number of acres required by soyabeans

= [ Amount of oil to be produced ] ÷ [ oil extracted per acre from soyabeans]

= 1,000 ÷ 50

= 20 acres

hence,

microalgae required less space.

7 0
3 years ago
Circle the numbers that are integers <br>5 --4 2.6 0.8 repeating and 100​
Lapatulllka [165]

Answer: 5, -4, 2.6, and 100

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
a small dog’s heart beats about 530,000,000 times during its lifetime, and a large dog’s heart beats about 1.4 times this amount
iren2701 [21]

Answer:

I think the answer is 742,000,000

Step-by-step explanation:

6 0
2 years ago
Given the weekly demand curve of a local wine producer is p= 50-0.1q, and that the total cost function is c= 1500+ 10q, where q
Mamont248 [21]

Answer:

Step-by-step explanation:

From the given information:

a) To express the weekly profit as a function of price

Cost =C(q) = 1500 + 10q

Revenue = p×q = (50 − 0.1q)×q = 50q - 0.1q²

Revenue = 50q - 0.1q²

Weekly profit = Revenue - Cost

P(q) = (50q -0.1q²) - (1500 + 10q)

P(q)= -0.1 q² + 40 q - 1500  

However, q = 500 - 10 p using p = 50 − 0.1q

P= -0.1 (500 - 10 p)² + 40 (500 - 10 p) - 1500

P= -10 p² + 600 p - 6500

b)

The price at which the bottle of the wine must be sold to realise a maximum profit can be determined by finding the derivative and then set it to 0  

P' = 0

= -20p+600 = 0

20p = 600

p = 600/20

p = $30

c)

The maximum profit that can be made by the producer is:

P= -10(30)² + 600(30) - 6500

P = - 9000 + 18000 - 6500

P = $2500

5 0
3 years ago
SOME PLEASE HELP ME WITH THIS ITS DUO TODAY​
Svet_ta [14]

Answer:

Blank above the 3: 9

Blanks underneath the 593: 540

Blanks underneath the line: 53

Blank by the "R": 53

Step-by-step explanation:

Simply divide.

3 0
3 years ago
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