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jok3333 [9.3K]
3 years ago
8

As part of a​ sixth-grade class​ project, the teacher brings to class a large jar containing 200 gumballs of two different​ colo

rs: red and green. Andy is asked to draw a sample of his own choosing and estimate the number of red gumballs in the jar. Andy draws a sample of 40 ​gumballs, of which 12 are red and 28 are green. Use​ Andy's sample to estimate the number of red gumballs in the jar. There are approximately how many red gumballs in the jar?
Mathematics
1 answer:
34kurt3 years ago
3 0
About 100 I’m not really sure but I tried
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Evaluate 3 + (a + 4)(8 - b) when a = 5 and b = 6.<br> The value of the expression is
levacccp [35]

Answer:

21

Step-by-step explanation:

you plug in 5 for a and 6 for b and solve.

8 0
3 years ago
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If 25% of 220 equals 5.5% of e what is w
coldgirl [10]
55=.055e
e=1,000
I’m not sure if you are looking for what e is but this is the answer for e.
3 0
4 years ago
Multiply and simplify to lowest terms when appropriate 11/9× 27/55
arsen [322]
11/9 * 27/55
First, you need to transform this expression to one fraction, by multiplying the numerators between each other and put the answer as one numerator, then the denominators and put the answer as one denominator.
11/9 * 27/55 = 297/495.
Now comes the simplifying. You need to divide both numerator and denominator by the same number, till you get an irreducible fraction (a fraction In which numerator and denominator can't be divided by the same number to get another whole number).
In this case, both 297 and 495 are divisible by 99.
297/99 = 3 and 495/99 = 5.
So 297/495 = 3/5.
3 and 5 can't be divided by a same number, so 3/5 represents the irreducible and simplified fraction.

You can re-check your answer (very important):
11/9 * 27/55 = 0.6
297/495 = 0.6
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11/9*22/55 = 297/495 = 3/5
The answer has been approved.

Hope this Helps! :) 
5 0
3 years ago
The average daily maximum temperature for Laura’s hometown can be modeled by the function f(x)=4.5sin(πx/6)+11.8 , where f(x) is
valina [46]

f(x) = 4.5sin(πx/6) + 11.8


January, x = 0

February, x = 1

an so on

May = 4


f(4) = 4.5sin(4π/6) + 11.8

f(4) = 4.5sin(2π/3) + 11.8


We know that π = 180° so,


f(4) = 4.5sin(360°/3) + 11.8

f(4) = 4.5sin(120°) + 11.8

f(4) = 4.5sin(60° + 60°) + 11.8


We know that:


sin(a + b) = sin a . cos b  + sin b . cos a

sin(60 + 60) = sin 60 . cos 60 + sin 60 . cos 60

sin(60 + 60) = 2.(sin 60 . cos 60)

sin(60 + 60) = 2.(√3/2 . 1/2)

sin(60 + 60) = 2.(√3/4)

sin(60 + 60) = √3/2


f(4) = 4.5*√3/2 + 11.8

f(4) = 2,25√3 + 11.8


√3 ≅ 1,73


f(4) = 2,25 . 1,73 + 11.8

f(4) = 13,7


The average daily maximum temperature in may is 13,7 °C

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3 years ago
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I need the answer to this question
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Look it up on google
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