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Citrus2011 [14]
3 years ago
11

Solve the system by elimination 1: x+5y-4z=-10, 2x-y+5z=-9, 2x-10y-5z=0 .. . 2. Solve the system by substitution: 2x-y+z=-4, z=5

, -2x+3y-z=-10. . . 3. A food store makes a 11–pound mixture of peanuts, almonds, and raisins. The cost of peanuts is $1.50 per pound, almonds cost $3.00 per pound, and raisins cost $1.50 per pound. The mixture calls for twice as many peanuts as almonds. The total cost of the mixture is $21.00. How much of each ingredient did the store use?
Mathematics
1 answer:
Kryger [21]3 years ago
8 0
1 )
1st and 2nd equation (multiply 1st by -2 ):
-2x - 10 y + 8 z = 20
2 x -  y    + 5 z = -9
---------------------------
       - 11 y + 13 z = 11  /  * ( -20 )
1st and 3rd:
- 2 x - 10 y + 8 z = 20
   2 x - 10 y - 5 z = 0
-----------------------------
         - 20 x + 3 z = 20  /  * 11
        ----------------------------------
         220 y - 260 z = -220
        - 220 y + 33 z = 220
        ------------------------------
                       z = 0,      y = -1,        x = - 5
2 )  
       2 x - y + 5 = -4
       - 2 x + 3 y - 5 = - 10
       Substitution: y = 2 x + 9
       - 2 x + 3(2 x + 9 ) = -5
        4 x = - 32,          x = -8,    y = -7,   z = 5
3 )
      x + y + z = 11
   1.5 x+3 y +1.5 z = 21
      x = 2 y
   ------------------------
      3 y + z = 11  / * (-2)
      6 y + 1.5 z = 21
    ------------------------
     - 6 y - 2 z = -22
       6 y + 1.5 z = 21
      ------------------------
                 -0.5 z = -1,           z = 2,   y = 3,   z = 6
Answer: the store used 6 pounds of peanuts, 3 pounds of almonds and 2 pounds of raisins. 
           
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worty [1.4K]

Given:

A figure of combination of hemisphere, cylinder and cone.

Radius of hemisphere, cylinder and cone = 6 units.

Height of cylinder = 12 units

Slant height of cone = 10 units.

To find:

The volume of the given figure.

Solution:

Volume of hemisphere is:

V_1=\dfrac{2}{3}\pi r^3

Where, r is the radius of the hemisphere.

V_1=\dfrac{2}{3}(3.14)(6)^3

V_1=\dfrac{6.28}{3}(216)

V_1=452.16

Volume of cylinder is:

V_2=\pi r^2h

Where, r is the radius of the cylinder and h is the height of the cylinder.

V_2=(3.14)(6)^2(12)

V_2=(3.14)(36)(12)

V_2=1356.48

We know that,

l^2=r^2+h^2                               [Pythagoras theorem]

Where, l is length, r is the radius and h is the height of the cone.

(10)^2=(6)^2+h^2

100-36=h^2

\sqrt{64}=h

8=h

Volume of cone is:

V_3=\dfrac{1}{3}\pi r^2h

Where, r is the radius of the cone and h is the height of the cone.

V_3=\dfrac{1}{3}(3.14)(6)^2(8)

V_3=\dfrac{25.12}{3}(36)

V_3=301.44

Now, the volume of the combined figure is:

V=V_1+V_2+V_3

V=452.16+1356.48+301.44

V=2110.08

Therefore, the volume of the given figure is 2110.08 cubic units.

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Step-by-step explanation:

20-6=14 (Distance between points) then 14*3/7=6.

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3/7 of the distance from A=6 to B=20 by adding 6 to 6.

6+6= 12

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3/7 from A=6 to B=20 is 12.

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