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mrs_skeptik [129]
3 years ago
9

Which is an exponential decay function? f(x) = 0.2(5/3)^x f(x)=-3.1^x f(x)=10^x f(x)=-2(0.7)^x

Mathematics
2 answers:
Serjik [45]3 years ago
4 0
-2(.7)^x is the only function where decay would be demonstrated of these
neonofarm [45]3 years ago
4 0

Answer:

D

F(x)= -2(0.7)x

Step-by-step explanation:

Just took the test

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OK here's the deal, I need to graph F(x)=x^2 and F(x)=2^x as functions. I've run completely out of options, I've graphed them as
butalik [34]

Answer:

see attached graph

Step-by-step explanation:

You graphs look fine.  The only thing I can think of without seeing the question itself, its that perhaps the teacher wants them on the same graph?

7 0
3 years ago
Given the parent functions f(x) = 3x 2 and g(x) = 5x − 10, what is g(x) − f(x)? (2 points)
Assoli18 [71]
$\begin{align} g(x)-f(x)&=(5x-10)-(3x+2)\\&=(5x-3x)+(-10-2)\\&=\boxed{2x-12} \end
8 0
3 years ago
Help me
Korolek [52]

Answer:

GIVE ME MY RAMEN

Step-by-step explanation:

3.

add like terms

30 + 7k = 100

100-30 = 70

70 divided by 7k = 10

k = 10

4. add the z's together

2z - 6 -2 = -10

+ 6 + 2

-10 will be -2 now since we dragged the -6 and -2 to the other side

2z = -2

z = -1

5. 3.2x - 1.7x = 1.5x

1.5x + 5.5 = 10

10 would be 4.5 since we dragged 5.5 to the other side so it would be 10 - 5.5

3.2x = 5.5

x = 1.71875

6.

3/4x - 1/4x = 2/4x

14 - 3 = 11

2/4x = 11

x = 22

7 0
3 years ago
Which expression has a value of 15 when n = 7? 43 minus 5 n 3 n minus 5 6 n minus 28 19 minus StartFraction 28 Over n EndFractio
andrey2020 [161]

Answer:

19-\dfrac{28}{n} is the expression with value of 15 when n = 7.

Step-by-step explanation:

To find the expression whose value is 15, substitute the value of n = 7 in each given expression.

Expression 1:

43-5n

Substituting the value of n,

43-5\left(7\right)

Simplifying,

43-35=8

Since the value of the expression is 8 which is not equal 15.

Hence expression 43-5n does not have value of 15 when n = 7.

Expression 2:

3n-5

Substituting the value of n,

3\left(7\right)-5

Simplifying,

21-5=16

Since the value of the expression is 16 which is not equal 15.

Hence expression 3n-5 does not have value of 15 when n = 7.

Expression 3:

6n-28

Substituting the value of n,

6\left(7\right)-28

Simplifying,

42-28=14

Since the value of the expression is 14 which is not equal 15.

Hence expression 6n-28 does not have value of 15 when n = 7.

Expression 4:

19-\dfrac{28}{n}

Substituting the value of n,

19-\dfrac{28}{7}

Simplifying,

19-4=15

Since the value of the expression is 15 which is equal 15.

Hence expression 19-\dfrac{28}{n} has the value of 15 when n = 7.

4 0
3 years ago
Read 2 more answers
I need some help please
Ganezh [65]
SOH CAH TOA tells you
  Cos(x) = Adjacent/Hypotenuse
so you can find
  x = arccos(24/28)
  x ≈ 31.0°
8 0
3 years ago
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