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AleksandrR [38]
2 years ago
8

Can you use mechanical pencils on the PSAT?

Mathematics
1 answer:
TEA [102]2 years ago
7 0

Answer:

no

Step-by-step explanation:

only number 2 pencils im pretty sure

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Rational numbers can be ______ or _______
chubhunter [2.5K]

Answer:

whole number or an integer.

Step-by-step explanation: hope this helps.

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3 years ago
In this activity, you will help Darin compare the unit prices, in price per pound, of clementines and navel oranges. Clementines
Alisiya [41]

Answer:

The table gives the cost for the number of three-pound bags of clementines. you need to change the number of bags to pounds to be able to get the data for the clementines in units of pounds and cost.

Step-by-step explanation:

each of the bags are three pounds each so 1 bag times 3, 2bags times 3, and then 3bags times 3, hope this answers your question.

4 0
3 years ago
The cost price of 16 notebooks is equal to the selling price of 12 notebooks.Find the gain per cent.
madam [21]

Answer:

Step-by-step explanation:

5 0
3 years ago
4|6-8| absolute value
sveta [45]
I think it’s 8 ( I’m not sure )
4 0
3 years ago
Read 2 more answers
Explain how to write a quadratic equation given the following three points on the graph (5,31) (3,11) (0,11)
masha68 [24]

Given:

The graph of a quadratic function passes through the points (5,31) (3,11) (0,11).

To find:

The equation of the quadratic function.

Solution:

A quadratic function is defined as:

y=ax^2+bx+c            ...(i)

It is passes through the point (0,11). So, substitute x=0,y=11 in (i).

11=a(0)^2+b(0)+c

11=c

Putting c=11 in (i), we get

y=ax^2+bx+11               ...(ii)

The quadratic function passes through the point (5,31). So, substitute x=5,y=31 in (ii).

31=a(5)^2+b(5)+11

31-11=a(25)+5b

20=25a+5b

Divide both sides by 5.

4=5a+b                  ...(iii)

The quadratic function passes through the point (3,11). So, substitute x=3,y=11 in (ii).

11=a(3)^2+b(3)+11

11-11=a(9)+3b

0=9a+3b

Divide both sides by 3.

0=3a+b                 ...(iv)

Subtracting (iv) from (iii), we get

4-0=5a+b-3a-b

4=2a

\dfrac{4}{2}=a

2=a

Putting a=2 in (iv), we get

0=3(2)+b

0=6+b

-6=b

Putting a=2,b=-6 in (ii), we get

y=(2)x^2+(-6)x+11

y=2x^2-6x+11

Therefore, the required quadratic equation is y=2x^2-6x+11.

7 0
2 years ago
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