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sergejj [24]
3 years ago
15

For each order pair ,determine whether is it a solution to 7x+4y=-23

Mathematics
1 answer:
trasher [3.6K]3 years ago
5 0

Simplifying

7x + -4y = 23


Solving

7x + -4y = 23


Solving for variable 'x'.


Move all terms containing x to the left, all other terms to the right.


Add '4y' to each side of the equation.

7x + -4y + 4y = 23 + 4y


Combine like terms: -4y + 4y = 0

7x + 0 = 23 + 4y

7x = 23 + 4y


Divide each side by '7'.

x = 3.285714286 + 0.5714285714y


Simplifying

x = 3.285714286 + 0.5714285714y

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8 0
3 years ago
20 points! Will mark the brainliest!
andrew-mc [135]
\dfrac{ \dfrac{x+3}{4x^2-16} }{ \dfrac{2x^2+10x+12}{2x-4} }

-----------------------------------------------------------------------------------
Write the divide fraction horizontally:
-----------------------------------------------------------------------------------

= \dfrac{x+3}{4x^2-16} \div \dfrac{2x^2+10x+12}{2x-4}

-----------------------------------------------------------------------------------
Factorise the numerators and denominators when possible:
-----------------------------------------------------------------------------------

= \dfrac{x+3}{4(x+2)(x-2)} \div \dfrac{ 2(x + 3) (x + 2)}{2(x-2)}

-----------------------------------------------------------------------------------
Convert the divide fraction to multiplication fraction
-----------------------------------------------------------------------------------

= \dfrac{x+3}{4(x+2)(x-2)} \times \dfrac{2(x-2)}{2(x+3)(x+2)}

-----------------------------------------------------------------------------------
Cancel the factors
-----------------------------------------------------------------------------------
= \dfrac{1}{4(x+2)} \times \dfrac{1}{(x+2)}

-----------------------------------------------------------------------------------
Combine to single fraction
-----------------------------------------------------------------------------------

= \dfrac{1}{4(x+2)^2}



4 0
3 years ago
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