F(x) -2x + 5; g(x) =3x²

Consider the volume of the region shown below, which shows a right circular cone with top radius 3 cm and height 10 cm. We have

koban [17]

I have the same problem here with a slight change in the given values:

radius is 2 & height of 6 indicates the bounding line is y = 3 x---> x = y / 3....

thus the [ π radius ² thickness ] yields π (y² / 9 ) dy , y in [ 0 , 6 ] for the volume... 

a Riemann sum is then : y_i = 0 + i [ 6 / n ] = 6 i / n , i = 1,2,3...n and do a right side sum

π Σ { i = 1,2,3..n } [ 36 i² / 9 n² ] [ 6 / n ]

I hope my guide has come to your help. God bless and have a nice day ahead!

5 0

3 years ago

A buoy floating in the sea is bobbing in simple harmonic motion with period 2 seconds and amplitude 8 in. Its displacement d fro

Mrac [35]

Answer:

The equation of the displacement $d$ as a function of time $t$ is :

$d(t)=8sin(\pi t+\pi )$

Step-by-step explanation:

Generally , A simple harmonic wave is a sinusoidal function that is it can be expressed in simple $sin$ or $cos$ terms.

Thus,

$d(t) = Asin(wt+c)$

is the general form of displacement of a SHM.

where,

$d(t)$ is the displacement with respect to the mean position at any time $t$
$A$ is amplitude
$w$ is the natural frequency of oscillation ( $rads^{-1}$ )
$c$ is the phase angle which indicates the initial position of the object in SHM ( $rad$ )

given,

Time period ( $T$ ) = $2s$
$A=8$
The natural frequency ( $w$ ) and time period ( $T$ ) is :

$w=\frac{2\pi} {T}$

∴

$w$ = $\frac{2\pi }{2} = \pi$ $rads^{-1}$

∴

the equation :

⇒ $d(t)=8sin(\pi t+c)$ ------1

since $d=0$ when $t=o$ ,

⇒ $0=8sinc\\c=n\pi$ ------2

where n is an integer ;

⇒since the bouy immediately moves in the negative direction , $x$ must be negative or c must be an odd multiple of $\pi$ .

⇒ $d(t) = 8sin(\pi t+(2k+1)\pi )$ ------3

where k is also an integer ;

the least value of $k=0$ ;

thus ,

the equation is :

$d(t)=8sin(\pi t+\pi )$

7 0

3 years ago

PLEASE HELP with these math questions (Please don't answer if you don't know all of them)

Leona [35]

Sqrt (53) = 10 * sqrt (0.53)

0.53 = 64/121
sqrt (0.53) = sqrt (64)/ sqrt (121) = 8/11 = 0.7273
Therefore sqrt (53) = 10 * 0.7273 = 7.27

sqrt (108) = 10 * sqrt (1.08)
sqrt (1.08) = sqrt (676/625) = 26/25 = 1.04
Therefore sqrt (108) = 10 * 1.04 = 10.4

sqrt (128) = 10 * sqrt (1.28)
sqrt (1.28) = sqrt (289/225) = 17/15 = 1.133
Therefore sqrt (108) = 10 * 1.133 = 11.33

5 0

3 years ago

The volume of a cube is the cube of the length of a side. If a side is S, the volume is S^3. What is the volume of a cube with s

sergij07 [2.7K]

Volume is a three-dimensional scalar quantity. The volume of the cube with side length of 4 inches is 64 inches³.

<h3>What is volume?</h3>

A volume is a scalar number that expresses the amount of three-dimensional space enclosed by a closed surface.

Given the volume of a cube is the cube of the length of a side. If a side is S, the volume is S^3. Therefore, the volume of cube with side 4 inches will be,

Volume of the cube = (4 in)³ = 64 in³

Hence, the volume of the cube with side length of 4 inches is 64 inches³.

Learn more about Volume:

brainly.com/question/13338592

#SPJ1

6 0

2 years ago

A structure covering a sports practice field has the shape of half of a cylinder, as shown. What is the total surface area of th

hoa [83]

wait i dont know why it wont let me comment or see comments but wheres the picture?

3 0

3 years ago