We know angle P is 90 degrees because of Thales Theorem, and angle N is 60 degrees. Because the angles in a triangle have to add up to 180 degrees, angle PMN has to be 30 degrees.
Angle QMO is half of angle PMN, so it's 15 degrees. Angle MQO is equal to angle QMO because the radii make Triangle OQM isosceles, so angle MQO is 15 degrees.
Answer:
The interest rate was 42.5%.
Step-by-step explanation:
Here we're applying a basic physics rule for vertical motion where the only pull on the object is gravity.
This rule has the form
h(t) = h + v t + (1/2)a*t^2
o o
To adapt this rule to this particular question replace h with 0, as the
o
upward path of the object begins at 0 ft. Replace v with +15 ft/sec.
o
Replace "a" with (-32.2 ft/(sec^2); this is the acceleration due to gravity.
Then we have the following, with the label F(t):
F(t) = 0 + (15 ft/sec)t + (1/2)(-32.2 ft)/(sec^2), or
F(t) = 15t - 16.1t^2. Thus, Choice D is correct.
Please note: To avoid confusion, please use " ^ " to denote exponentiation:
F(t) = -16t^2 + 15t
$5.25? i think, im sorry if im wrong
Answer:
A
Step-by-step explanation:
Photomath, lol
