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iren [92.7K]
2 years ago
7

How can you find vertex, x intercepts and y intercepts

Mathematics
1 answer:
slavikrds [6]2 years ago
3 0
The vertex of a quadratic equation is the minimum or maximum point of the equation. Find that, and you have the vertex. <span>To </span>find the x-intercept<span> of a given linear equation, plug in 0 for 'y' and solve for '</span>x'. To find<span> the y-</span>intercept, plug 0 in for 'x<span>' and solve for 'y'.</span>
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In an old story, a man puts 2 grains of rice on the first space of a chess board. He puts 4 grains on the second space, 8 grains
denis23 [38]
We know that
a1----------> <span>grains of rice in the first square
a1=2
n------------> space ubication
the expressions  is
 an=a1</span>^n----------> an=2<span>^n

for the </span><span>the tenth space  n=10
</span>an=2^10---------> an=1024 grains of rice

the answer is
1024 grains of rice

5 0
2 years ago
Read 2 more answers
Joshua is 1.45 meters tall. At 2 p.m., he measures the length of a tree's shadow to be 31.65 meters. He stands 26.2 meters away
Lena [83]

Answer:

The height of the tree=8.42 m

Step-by-step explanation:

We are given that

Height of Joshua, h=1.45 m

Length of tree's shadow, L=31.65 m

Distance between tree and Joshua=26.2 m

We have to find the height of the tree.

BC=26.2 m

BD=31.65m

CD=BD-BC

CD=31.65-26.2=5.45 m

EC=1.45 m

All right triangles are similar .When two triangles are similar then the ratio of their corresponding sides are equal.

\triangle ABD\sim \triangle ECD

\frac{AB}{EC}=\frac{BD}{CD}

Substitute the values

\frac{AB}{1.45}=\frac{31.65}{5.45}

AB=\frac{31.65\times 1.45}{5.45}

AB=8.42m

Hence, the height of the tree=8.42 m

6 0
2 years ago
Divide three fourths ÷ two fifths
KengaRu [80]
Your answer would be on eof the three
15/8
1.875
1 7/8
Hope this helps...
7 0
2 years ago
Read 2 more answers
wolverine and cyclops ordered large pizzas for dinner. Wolverine ate 1-3/8 pizzas and cyclops ate 1/12 of a pizza. which of the
Lilit [14]

Answer:

What statements are you talking about

Step-by-step explanation:

6 0
2 years ago
Over which interval is the graph of f(x) = –x2 + 3x + 8 increasing?
vivado [14]
Hello there!

To find the increasing intervals for this graph just based on the equation, we should find the turning points first.

Take the derivative of f(x)...
f(x)=-x²+3x+8
f'(x)=-2x+3

Set f'(x) equal to 0...
0=-2x+3
-3=-2x
3/2=x

This means that the x-value of our turning point is 3/2. Now we need to analyze the equation to figure out the end behavior of this graph as x approaches infinity and negative infinity.
Since the leading coefficient is -1, as x approaches ∞, f(x) approaches -∞ Because the exponent of the leading term is even, the end behavior of f(x) as x approaches -∞ is also -∞.

This means that the interval by which this parabola is increasing is...
(-∞,3/2)

PLEASE DON'T include 3/2 on the increasing interval because it's a turning point. The slope of the tangent line to the turning point is 0 so the graph isn't increasing OR decreasing at this point.

I really hope this helps!
Best wishes :)
7 0
3 years ago
Read 2 more answers
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