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alexandr402 [8]
3 years ago
6

Find the slope of the line passing through the points A(6, –5) and B(–5, –7).

Mathematics
2 answers:
Llana [10]3 years ago
8 0

Answer:

m= \frac{2}{11}

Step-by-step explanation:

inna [77]3 years ago
6 0

Answer:

-13/1

Step-by-step explanation:

y2 - y1 / x2 - x1 to find slope

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The data shown in the table below can be
kvv77 [185]

Answer:

6: 12

7: 14

8: 16

Step-by-step explanation:

You do the last (y) term given [18] minus the first (y) term [10] given divided by how many terms it takes to get from the last (y) term given minus the first (y) term given [4]. So the equation looks like this:

(18 - 10)/4= 8/4 = 2

4 0
2 years ago
Sarah has 4 cousins. Melanie has 7 times as many cousins as Sarah. How many Cousins dose Melanie have?​
Lina20 [59]

Answer:

Melanie has 28 cousins.

Step-by-step explanation:

4 x 7 = 28

I hope this helped and if it did I would appreciate it if you marked me Brainliest. Thank you and have a nice day!

5 0
2 years ago
Read 2 more answers
Find the sum of a finite geometric series. The Smiths spent $2,000 on clothes in a particular year. If they increase the amount
boyakko [2]

\bf \stackrel{\textit{first year}}{2000}~~,~~\stackrel{\textit{second year}}{2000+\stackrel{\textit{10\% of 2000}}{\frac{2000}{10}}}\implies 2200

now, if we take 2000 to be the 100%, what is 2200? well, 2200 is just 100% + 10%, namely 110%, and if we change that percent format to a decimal, we simply divide it by 100, thus \bf 110\%\implies \cfrac{110}{100}\implies 1.1.

so, 1.1 is the decimal number we multiply a term to get the next term, namely 1.1 is the common ratio.

\bf \qquad \qquad \textit{sum of a finite geometric sequence}\\\\S_n=\sum\limits_{i=1}^{n}\ a_1\cdot r^{i-1}\implies S_n=a_1\left( \cfrac{1-r^n}{1-r} \right)\quad \begin{cases}n=n^{th}\ term\\a_1=\textit{first term's value}\\r=\textit{common ratio}\\----------\\a_1=2000\\r=1.1\\n=4\end{cases}\\\\\\S_4=2000\left[ \cfrac{1-(1.1)^4}{1-1.1} \right]\implies S_4=2000\left(\cfrac{-0.4641}{-0.1}  \right)\\\\\\S_4=2000(4.641)\implies S_4=9282

7 0
2 years ago
Please help i’m in a hurry
Wittaler [7]

Answer:

the answer should be 18

Step-by-step explanation:

this isnt exactly hard when you get the first part with ST beeing 36 then you can just halve that and the answer is 18

6 0
3 years ago
The weight of people in a small town in Missouri is known to be normally distributed with a mean of 186 pounds and a standard de
OleMash [197]

Answer:

the probability that a random sample of 17 persons will exceed the weight limit of 3,417 pounds is 0.0166

Step-by-step explanation:

The summary of the given statistical data set are:

Sample Mean = 186

Standard deviation = 29

Maximum capacity 3,417 pounds or 17 persons.

sample size = 17

population mean =3417

The objective is to determine the probability  that a random sample of 17 persons will exceed the weight limit of 3,417 pounds

In order to do that;

Let assume X to be the random variable that follows the normal distribution;

where;

Mean \mu = 186 × 17 = 3162

Standard deviation = 29* \sqrt{17}

Standard deviation = 119.57

P(X>3417) = P(\dfrac{X - \mu}{\sigma}>\dfrac{X - \mu}{\sigma})

P(X>3417) = P(\dfrac{3417 - \mu}{\sigma}>\dfrac{3417 - 3162}{119.57})

P(X>3417) = P(Z>\dfrac{255}{119.57})

P(X>3417) = P(Z>2.133)

P(X>3417) =1- 0.9834

P(X>3417) =0.0166

Therefore; the probability that a random sample of 17 persons will exceed the weight limit of 3,417 pounds is 0.0166

5 0
3 years ago
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