How many males and how many females would there be if the total enrollment is 15000?
Ratio is
90 males 15000 - x
------------- = ---------------
125 fem x
Then 90x = 1875000 - 125x, or 215x = 1875000
x = approx 8720 females
and 15000-8720, or 6279 males
If every male finds a dance partner, that would leave (8720-6279) females, or 2440, without dance partners. ;(
Check: is the male:female ratio near 90:125?
Is 6279:8720 approx equal to 90:125?
Yes. 0.72 (approx) = 0.72 (approx).
Option B
We can store a total of 360 songs in 60 megabytes of space.
<u>Solution:</u>
It is given to us that It takes 24 megabytes to store 144 songs on a music player. We have been asked to find out what is the greatest number of songs that 60 megabytes could store.
To solve this question we can use the unitary method.
We will first find out how many songs can be stored in 1 megabyte. This can be done as follows:

Therefore, we can store 6 songs in 1 megabyte.
So, in 60 megabyte we can store the following number of songs:

So, we can store a total of 360 songs in 60 megabytes.
Answer: write a triangle and a quad.
no.
Step-by-step explanation:
Answer:
52
Step-by-step explanation:

Substitute values given:

Simplify:
64-14+2
50+2
52
Therefore 52 is our answer
Answer:
B. Add 115+500 then subtract 3
C. Add 112+500
Step-by-step explanation:
Any strategy that gives a sum of 612 will work. Strategy A gives a sum of 602, so is not useful.
The appropriate choices are B and C.
B: 115 +497 = 115 +(500 -3) = (115 +500) -3
C: 115 +497 = 115 +497 -3 +3 = (115 -3) +(497 +3) = 112 +500