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3 years ago

What product does the model show?

Mathematics

2 answers:

Anika [276]3 years ago

8 0

Please tell me
thats what it says

Karolina [17]3 years ago

4 0

What model? It only says please help me lol

You might be interested in

What is the difference of 29.34 – 14.24? Pleasee help.

Delicious77 [7]

Answer:

15.1

Step-by-step explanation:

29.34

-14.24

---------

15.10

8 0

2 years ago

The cost of 4 pounds of bananas is $3.52. What is the constant of proportionality that relates the cost of dollars, y, to the nu

Sladkaya [172]

.88
3.52 divided by 4

6 0

3 years ago

Use the information provided to determine a 95% confidence interval for the population variance. A researcher was interested in

Leno4ka [110]

Answer:

The 95% confidence interval for the population variance is (8.80, 32.45).

Step-by-step explanation:

The (1 - α)% confidence interval for the population variance is given as follows:

$\frac{(n-1)\cdot s^{2}}{\chi^{2}_{\alpha/2}}\leq \sigma^{2}\leq \frac{(n-1)\cdot s^{2}}{\chi^{2}_{1-\alpha/2}}$

It is provided that:

n = 20

s = 3.9

Confidence level = 95%

⇒ α = 0.05

Compute the critical values of Chi-square:

$\chi^{2}_{\alpha/2, (n-1)}=\chi^{2}_{0.05/2, (20-1)}=\chi^{2}_{0.025,19}=32.852\\\\\chi^{2}_{1-\alpha/2, (n-1)}=\chi^{2}_{1-0.05/2, (20-1)}=\chi^{2}_{0.975,19}=8.907$

*Use a Chi-square table.

Compute the 95% confidence interval for the population variance as follows:

$\frac{(n-1)\cdot s^{2}}{\chi^{2}_{\alpha/2}}\leq \sigma^{2}\leq \frac{(n-1)\cdot s^{2}}{\chi^{2}_{1-\alpha/2}}$

$\frac{(20-1)\cdot (3.9)^{2}}{32.852}\leq \sigma^{2}\leq \frac{(20-1)\cdot (3.9)^{2}}{8.907}\\\\8.7967\leq \sigma^{2}\leq 32.4453\\\\8.80\leq \sigma^{2}\leq 32.45$

Thus, the 95% confidence interval for the population variance is (8.80, 32.45).

4 0

3 years ago

In a test of a gender-selection technique, results consisted of 229 baby girls and 7 baby boys. Based on this result, what is

kirill115 [55]

Answer:

I'm pretty sure that the answer would be 229/236.

Step-by-step explanation:

Ok so. Since the results of the test is 229 for a girl and the results for a boy is 7. So i'm pretty sure what to do is combine both the results and keep that as the denominator. And then the numerator will be the result. So in this case the numerator would be 229 and the denominator would be 236.

I hope this helped, have a great day!!!

3 0

3 years ago

Use the pythagoren theorem to solve x

defon

Well the equation is (A^2)+(B^2)=(C^2)

A= x
B= 2x
C will always be the longest side because it is the Hypotenuse = 25

So if you plug in those numbers into the equation...

(x^2) + (2x^2) = (25^2)

x^2 + 4x^2 = 625

Combine like terms

5x^2 = 625

Divide by five to both sides

x^2 = 125

Then Square root,

x = sqrt(125)

x = sqrt(25* 5)

x = 5sqrt(5)

3 0

3 years ago