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noname [10]
3 years ago
10

Please help. Solve 2 - 4

Mathematics
2 answers:
Alex777 [14]3 years ago
7 0

Answer:

2. 1080

3. 56

4. $1665

Step-by-step explanation:

2. 1080 (/6), 180 (/6), 30 (/6), 5

3. 4(6 + 8) = 4 x 14 = 56

4. $75 + 30(53) = $75 + 1590 = $1665

Afina-wow [57]3 years ago
3 0
-2
when u subtract regularly the answers 2. but since -4 has more negatives, the answer will be negative
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The Chartered Financial Analyst (CFA) designation is fast becoming a requirement for serious investment professionals. Although
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Answer:  ($141,775, $158,225)

Step-by-step explanation:

Given : Significance level : \alpha: 1-0.9=0.1

Critical value : z_{\alpha/2}=1.645

Sample size : n= 49

Sample mean : \overline{x}=150,000

Standard deviation : \sigma=35,000

The confidence interval for population mean is given by :_

\overline{x}\pm z_{\alpha/2}\dfrac{\sigma}{\sqrt{n}}

= 150,000\pm (1.645)\dfrac{35000}{\sqrt{49}}\\\\\approx150,000\pm8225\\\\=(150,000-8225,150,000+8225)=(141,775,158,225)

Hence,he 90% confidence interval for the average salary of a CFA charter-holder = ($141,775, $158,225)

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At the pet store, 3 cats are brown with stripes, 2 cats are orange with stripes, and 5 cats are solid brown. What is the probabi
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The probability of a cat being brown would be 4/5 and the probability of a cat having stripes would be 1/2.
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2.63 According to Consumer Digest (July/August 1996), the probable location of personal computers (PC) in the home is as follows
PolarNik [594]

Answer:

a) 0.32

b) 0.68

c) office or den

Step-by-step explanation:

Locations             Probabilities

Adult bedroom    0.03

Child bedroom    0.15

Other bedroom   0.14

Office or den       0.40

Other rooms        0.28

a)

P(PC in bedroom)= P(PC in adult bedroom)+ P(PC in child bedroom)+ P(PC in other bedroom)

P(PC in bedroom)= 0.03+0.15+ 0.14

P(PC in bedroom)= 0.32.

Thus, the probability that a PC is in a bedroom is 0.32.

b)

P(PC is not in bedroom)= P(PC in Office or den)+ P(PC in Other rooms)

P(PC is not in bedroom)= 0.40+0.28

P(PC is not in bedroom)= 0.68.

Thus, the probability that a PC is not in a bedroom is 0.68.

c)

When a household is selected at random from households with a PC we would expect to find a PC in a room which has a greater probability of having PC.

The greater probability of room having a PC is of Office or den room with probability 0.40. So, when a household is selected at random from households with a PC we would expect to find a PC in a Office or den room.

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