The equation y=ax2+bx+c goes through the coordinates (-6, 15), (0, -3), and (2, 7). What are the values of a, b, and c?

Mathematics

1 answer:

Romashka-Z-Leto [24]3 years ago

7 0

The typical method of solving this question... (School method)

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783 rounded to the nearest hundred is

miss Akunina [59]

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3 years ago

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The wall is 12 feet long. They are placing studs every 18 inches. If there are studs on each end of the wall, how many studs wil

Oliga [24]

Answer:

Step-by-step explanation:

1 feet is 12 inches, so 12 feet is 12 * 12 = 144 inches.

If studs are placed 18 inches apart, in 144 inches, there will be:

$\frac{144}{18}=8$

But remember, there is a stud at the very beginning (at 0 feet).

So in total there are going to be 9 studs

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4 years ago

I NEED HELP ON THIS PROBLEM!!! PLEASE

Allushta [10]

keeping in mind that perpendicular lines have negative reciprocal slopes, let's check for the slope of the equation above

$5x+8y=-9\implies 8y=-5x-9\implies y=\cfrac{-5x-9}{8} \\\\\\ y=\stackrel{\stackrel{m}{\downarrow }}{-\cfrac{5}{8}} x-9\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}$

well then, so since this equation has that slope therefore

$\stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{\cfrac{-5}{8}} ~\hfill \stackrel{reciprocal}{\cfrac{8}{-5}} ~\hfill \stackrel{negative~reciprocal}{-\cfrac{8}{-5}\implies \cfrac{8}{5}}}$

so we're really looking for the equation of a line whose slope is 8/5 and runs through (10,10)

$(\stackrel{x_1}{10}~,~\stackrel{y_1}{10}) ~\hspace{10em} \stackrel{slope}{m}\implies \cfrac{8}{5} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{10}=\stackrel{m}{\cfrac{8}{5}}(x-\stackrel{x_1}{10})$