This can be solved by factoring.
First, set the expression equal to zero.

Then, find two the factors of

whose sum is

.

Split

into these two factors.

Next, factor by grouping.

By the Zero Product Property, set each factor equal to zero.


These are the solutions. The Complex Conjugate Root Theorem and the Fundamental Theorem of Algebra both state that, in essence, real and imaginary solutions come in pairs of two and every polynomial of degree

has exactly

complex roots, but real roots are also complex roots. That sounds confusing, but this just means that you're done.
Your answers are -2 and 1/3. There are two real roots.
Answer:
1+1 is 2
Step-by-step explanation:
Step-by-step explanation:
Before we answer, the area of a Circle given it radius is

The area of a circle given it diameter is

So let answers question 1-4.
1. The area is

2. The area is

3.

4.

For the 5th problem, circumference is

where d is the diameter and

where r is the radius.
A circumference of 100 m means the radius is 50 because


So this means the area is

Y=40x+100 and the second question is y=1.69x
Answer:
The discriminant is the part under the square root in the quadratic formula, b²-4ac. If it is more than 0, the equation has two real solutions. If it's less than 0, there are no solutions. If it's equal to 0, there is one solution.
Brainliest please
Step-by-step explanation: