I am not quite sure what the question asks for,
But this is what i assume it wants:
Cos A= 0.6489
In this given one, we basically find the size of the angle A
we do cosine inverse on both sides to get the size of the angle A
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: It looks like this in the calculator
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× cos A=
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(0.6489)
(
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and cos cancels out)
A=
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(0.6489)
A=49.54°
check:
cos 49.54=0.6489 (its right!)
Answer:
19 degrees
Step-by-step explanation:
From the question given
The interior angles are x+12 and x - 3
Exterior angle is <IJK = 5x-6
Using the rule that states that the sum of interior angle of a triangle is equal to the exterior
<JHI + <HIJ = <IJK
x+12 + x-3 = 5x - 6
2x+9 = 5x -6
2x - 5x = -6-9
-3x = -15
x = -15/-3
x = 5
Get <IJK
Recall that <IJK = 5x - 6
<IJK = 5(5) - 6
<IJK = 25-6
<IJK = 19 degrees
Hence the measure of <IJK is 19 degrees
Really true. just wanting points is not a reason to mess with someone else.
The set of x ordinates or {1,2,3}
Part A - 226.865 or 226.87
Part B - 120
Part C - 106.865