C.) 5, Using P.E.M.D.A.S you have to multiply first, so replacing the variable X with 5, it should look like this: (6*5) -3=27. 6*5 is 30, 30 subtracted by 3 is 27.
One worker<span> produces an average of 84 units per </span>day<span> with a street </span>What is the probability<span> that in any </span>single day worker 1 will outproduce worker 2<span>? A) 0.1141.
</span>
Answer, factory worker productivity<span> is </span>normally distributed<span>. </span>One worker produces<span> an </span>average<span> of 75 </span>units per day<span> with a standar, day with a </span>standard deviation<span> of 20. </span>Another worker produces<span> at an </span>average rate<span> of 65 </span><span>per day.
</span>
Answer:
10%
Step-by-step explanation:
We know Perimeter of rectangle
= 2 (Length + Width)
If width and length are increased by 10%
New length= L + 10/100L = (1.1) L
New width = W + 10/100W = (1.1) W
Perimeter = 2 [(1.1) L + (1.1) W]
Perimeter = 2 (1.1) (L + W)
Perimeter = (2.2) (L + W)
Increase in perimeter = 2.2 (L + W) - 2 (L + W)
The increase in Perimeter = 0.2 (L + W)
Percent increase
= 0.2 (L + W)/2 (L + W) × 100
= 0.2/2 × 100
= 0.1 × 100
= 10%
I hope this helped and if it did, please mark as Brainliest.
