If you would like to know for how many days will 1/2 of a bag of dog food last, you can calculate this using the following steps:
1 day ... 3 bags of dog food
x days = ? ... 1/2 of a bag of dog food
1 * 1/2 = 3 * x
1/2 = 3 * x /3
x = 1/2 * 1/3
x = 1/6 of a day
The correct result would be 1/6 of a day.
A=number of seats in section A
B=number of seats in section B
C=number of seats in section C
We can suggest this system of equations:
A+B+C=55,000
A=B+C ⇒A-B-C=0
28A+16B+12C=1,158,000
We solve this system of equations by Gauss Method.
1 1 1 55,000
1 -1 -1 0
28 16 12 1,158,000
1 1 1 55,000
0 -2 -2 -55,000 (R₂-R₁)
0 12 16 382,000 (28R₁-R₂)
1 1 1 55,000
0 -2 -2 -55,000
0 0 4 52,000 (6R₂+R₃)
Therefore:
4C=52,000
C=52,000/4
C=13,000
-2B-2(13,000)=-55,000
-2B-26,000=-55,000
-2B=-55,000+26,000
-2B=-29,000
B=-29,000 / -2
B=14,500.
A + 14,500+13,000=55,000
A+27,500=55,000
A=55,000-27,500
A=27,500.
Answer: there are 27,500 seats in section A, 14,500 seats in section B and 13,000 seats in section C.
What is the lower quartile, Q1, of the following data set? 48, 43, 34, 59, 62, 75, 30, 71, 37, 66, 53, 21, 40, 56, 25
Stolb23 [73]
I believe the answer is 34. I plugged the values into the STAT button on my graphing calculator and went into 1-Var Stats.
Unable to submit.
Says incorrect answer
Answer:
3/
10
= 0.3
Step-by-step explanation:
Multiple: 2/5
* 3/4
= 2 · 3/5· 4
= 6/20
= 3 · 2/10 · 2
= 3/10
Multiply both numerators and denominators. Result fraction keep to lowest possible denominator GCD(6, 20) = 2. In the following intermediate step, cancel by a common factor of 2 gives 3/
10
.
In other words - two fifths multiplied by three quarters = three tenths.
