Answer:
Average ROC = 0
Step-by-step explanation:
Average ROC : (f(b) - f(a)) / (b - a) ... slope = (y'-y) / (x'-x)
a = -3 f(a) = 10 ... x=-3, y=10
b = 6 f(b) = 10 ... x'=6, y'=10
Average ROC = (10 - 10) / (6 - -3) = 0 / 9 = 0
Answer:
its 133
Step-by-step explanation:
50 fits into 6650 133 times. u cant show a pic but if you know division, its easy.
Answer: 2.8
Step-by-step explanation:
The mean of the data set it 10. Then find the difference between the mean and each data value. |10-5|=5 do this for all of them. You get 5,1,1,1,6. Now find the mean of the these new data value. 5+1+1+1+6=14 14/5=2.8
The question is incomplete. Here is the complete question.
As a part of city building refurbishment project, architects have constructed a scale model of several city builidings to present to the city commission for approval. The scale of the model is 1 inch = 9 feet.
The model includes a new park in the center of the city. If the dimensions of the park in the model are 9 inches by 17 inches, what are the actual dimensions of the park?
Answer: 81 feet by 153 feet
Step-by-step explanation: <u>Unit</u> <u>Scale</u> is a ratio comparing actual dimensions of an object to the dimensions of model representing the actual object.
In the refurbishment project, the unit scale is given by
1 inch = 9 feet
So, the dimensions of the new park in actual dimensions would be
1 inch = 9 feet
9 inches = x
x = 9.9
x = 81 feet
1 inch = 9 feet
17 inches = y
y = 17.9
y = 153 feet
The actual dimensions of the new park are 81 feet by 153 feet.