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vitfil [10]
3 years ago
6

times 10" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
denis-greek [22]3 years ago
7 0

Answer:

123

Step-by-step explanation:

To solve this question,

you can use BODMAS THEORY

That means,

B - brackets

O - of

D - division

M - multiplication

A - addition

S - subtraction

Now you can solve the sum like this.

13 + 11 × 10

13 + 110

= 123

Hope this helps you.

Let me know if you have any other questions :-)

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Simplify secxcscx/1+tan^2x.
frosja888 [35]

Answer:

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Step-by-step explanation:

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3 years ago
Advertisements for the Sylph Physical Fitness Center claim that completion of their course will result in a loss of weight (meas
MrMuchimi

Answer:

90% confidence interval for the mean weight loss for the population represented by this sample assuming that the differences are coming from a normally distributed population is [1.989 ,13.5105]

Step-by-step explanation:

The data given is

                        Mean                 Std Dev

Before            177.25                29.325

After              169.50                    22.431

Difference        7.75                    8.598

Hence d`=   7.75 and sd=   8.598

The 90% confidence interval for the difference in means for the paired observation is given by

d` ± t∝/2(n-1) *sd/√n

Here  t∝/2(n-1)=1.895  where n-1= 8-1= 7 d.f

and  ∝/2= 0.1/2=0.05

Putting the values

d` ± t∝/2(n-1) *sd/√n

7.75  ±1.895 *  8.598 /√8

 7.75  ± 5.7605

1.989 ,13.5105

90% confidence interval for the mean weight loss for the population represented by this sample assuming that the differences are coming from a normally distributed population is [1.989 ,13.5105]

3 0
3 years ago
A passenger train traveled 100 miles in the same amount of time it took a freight train to travel 80 miles. The rate of the frei
andreev551 [17]

Answer:

The passenger train traveled at a speed of 25 miles/hour

Step-by-step explanation:

In this question, we are asked to calculate the rate at which a particular passenger train is traveling.

We use the information in the question to answer as follows;

Firstly, we identify that they traveled at the same time but their distances are different. This means that their speed must be different also.

Mathematically, we know that time can be calculated as distance/ time.

Let us say the speed at which the passenger train traveled is x miles per hour. This means that the speed of the freight train which was 5 miles per hour slower would be (x-5) miles per hour.

We know their times are equal;

Hence;

100/x = 80/(x-5)

We cross multiply

100(x-5) = 80x

100x -500 = 80x

100x-80x = 500

20x = 500

x = 500/20

x = 25 miles per hour

6 0
4 years ago
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