X=3 ex:3-8=-5 and -5x4=-20 -20+14=-6
Step-by-step explanation:
wnich grade you are in
please answer fast
Answer:
It's cot x :)
Step-by-step explanation:
I'm not really good at explaining,but I know that's the answer :))
Answer:
90% confidence interval for the mean weight loss for the population represented by this sample assuming that the differences are coming from a normally distributed population is [1.989 ,13.5105]
Step-by-step explanation:
The data given is
Mean Std Dev
Before 177.25 29.325
After 169.50 22.431
Difference 7.75 8.598
Hence d`= 7.75 and sd= 8.598
The 90% confidence interval for the difference in means for the paired observation is given by
d` ± t∝/2(n-1) *sd/√n
Here t∝/2(n-1)=1.895 where n-1= 8-1= 7 d.f
and ∝/2= 0.1/2=0.05
Putting the values
d` ± t∝/2(n-1) *sd/√n
7.75 ±1.895 * 8.598 /√8
7.75 ± 5.7605
1.989 ,13.5105
90% confidence interval for the mean weight loss for the population represented by this sample assuming that the differences are coming from a normally distributed population is [1.989 ,13.5105]
Answer:
The passenger train traveled at a speed of 25 miles/hour
Step-by-step explanation:
In this question, we are asked to calculate the rate at which a particular passenger train is traveling.
We use the information in the question to answer as follows;
Firstly, we identify that they traveled at the same time but their distances are different. This means that their speed must be different also.
Mathematically, we know that time can be calculated as distance/ time.
Let us say the speed at which the passenger train traveled is x miles per hour. This means that the speed of the freight train which was 5 miles per hour slower would be (x-5) miles per hour.
We know their times are equal;
Hence;
100/x = 80/(x-5)
We cross multiply
100(x-5) = 80x
100x -500 = 80x
100x-80x = 500
20x = 500
x = 500/20
x = 25 miles per hour
