How to solve this equation
1 answer:
You might be interested in
210 children tickets are sold
<em><u>Solution:</u></em>
Let "x" be the number of child tickets sold
Let "y" be the number of adult tickets sold
Cost of 1 adult ticket = $ 7
Cost of 1 child ticket = $ 3
<em><u>Given that 370 people bought tickets to a fair</u></em>
number of child tickets sold + number of adult tickets sold = 370
x + y = 370 ------ eqn 1
<em><u>Total revenue was $1750. Therefore,</u></em>
number of child tickets sold x Cost of 1 child ticket + number of adult tickets sold x Cost of 1 child ticket = 1750
3x + 7y = 1750 ------ eqn 2
<em><u>Let us solve eqn 1 and eqn 2</u></em>
From eqn 1,
x = 370 - y ------- eqn 3
<em><u>Substitute eqn 3 in eqn 2</u></em>
3(370 - y) + 7y = 1750
1110 - 3y + 7y = 1750
4y = 1750 - 1110
4y = 640
<h3>y = 160</h3>From eqn 3,
x = 370 - 160
<h3>x = 210</h3>Thus 210 children tickets are sold