Answer:
28.25
Step-by-step explanation:
Solution:
we are given that
Clayton needs to reflect the triangle below across the line y=x.
And as we know the reflection of the point (x,y) across the line y = x is the point (y, x).
Hence the new Traingle will be on the other side of the line y=x and position of x and y-coordinates of the vertices of the trangle gets interchanged.
Hence the Options that applies are:
C’ will move because all points move in a reflection.
The image and the pre-image will be congruent triangles. (Because reflection just changes the position of the trinagle not the property)
The image and pre-image will not have the same orientation because reflections flip figures.
<span>Left & Right affect the h,
Up & Down affect the k,
Shrink & Stretch affect the "a" (which is in front of the absolute value expression).
1. shift 1 unit to the right and up 2 units → y = |x-1| + 2
2. </span><span>shift 3 units to the left and 7 units down → y = |x + 7| - 7
3. </span><span>vertical shrink by a factor of 1/3 → y =

|x|
4. </span><span>vertical stretch by a factor of 3
→ y = </span><span>3 |x|</span>
You need to make a series of equations from what you are given first. I am going to use the first letter of each of the names to represent the length of that persons wire.
1/2s=2/5d
3c=s
s+d+c=6 ft
Okay. Now you can combine the first two equations knowing what s equals:
1/2(3c)=2/5d
d=15c/4
Now you have d=15c/4 and s=3c, so you can replace d and s in the third equation.
3c+15c/4+c=6
Then solve for c and plug it into the equation 3c=s to find the length of sarah's wire.
Answer:
a line segment ✓....,.........