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Required five terms of sequence are 19 , 12 , 5 , -2 and -9 .
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Solution:
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Need to find the five terms of the sequence.
Given recursive rule is f(x) = f(x-1) -7
Substituting x = 2 , f(2) = f(2-1)-7
= f(2) = f(1) – 7 ------(1)
Also given that f(2) = 12.
On substituting the given value of f(2) in eq (1) we get
12 = f(1) – 7
f(1) = 12 + 7 = 19
Using given recursive rule and given value of f(2) calculating f(3)
Substituting x = 3 ,
f(3) = f(3-1) – 7
= f(2) – 7
= 12 – 7
= 5
Using given recursive rule and calculated value of f(3) calculating f(4)
Substituting x = 4,
f(4) = f(4-1) – 7
= f(3) – 7
= 5– 7
= -2
Using given recursive rule and calculated value of f(4) calculating f(5)
Substituting x = 5,
f(5) = f(5-1) – 7
= f(4) – 7
= -2– 7
= -9
Hence required five terms of sequence are 19 , 12 , 5 , -2 and -9 .
Answer:
Area of Circle 1=>64(pi) units^2
Area of Circle 2=>9(pi) units^2
Step-by-step explanation:
Circumference=2(pi)r
Circle 1: 2(pi)r=16(pi)
Divide by 2(pi) on both sides
r=8 units
Area=(pi)r^2
Area of circle 1=>(pi)*(8^2)
Area of Circle 1=>64(pi) units^2
Circle 2: 2(pi)r=6(pi)
Divide by 2(pi) on both sides
r=3 units
Area=(pi)r^2
Area of circle 2=>(pi)*(3^2)
Area of Circle 2=>9(pi) units^2
Answer:if it’s a pretest just guess you don’t need to get it right
Step-by-step explanation:
Answer:
(a) (6, 2)
Step-by-step explanation:
The system of equations has one of them in y= form, so it lends itself to solution by substitution.
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Using the equation for y to substitute into the first equation, we have ...
2x -y = 10
2x -(-1/2x +5) = 10 . . . . . substitute for y
2x +1/2x -5 = 10 . . . . . eliminate parentheses
5/2x = 15 . . . . . . . . . add 5, collect terms
x = 6 . . . . . . . . . . . multiply by 2/5
Using the equation for y, we have ...
y = -1/2(6) +5 = -3 +5
y = 2
The solution is (x, y) = (6, 2).
