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madam [21]
3 years ago
14

What is the diagonal of a 16×12 inch tv

Mathematics
1 answer:
mamaluj [8]3 years ago
5 0

Answer:

the diagonal of TV equal to 20

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Rami uses chalk to draw a rectangle with a length of 4 1/2 yards.
Makovka662 [10]

Answer:

162 inches

Step-by-step explanation:

1 yard = 36 in

36 × 4 1/2 ( or 4.5) =162

Hope dis helps :3  o(* ̄▽ ̄*)ブ

3 0
3 years ago
Read 2 more answers
A circular garden has a circumference of
omeli [17]

This solution to this problem is predicated on the fact that the circumference is just: 2\pir. A straight line going through the center of the garden would actually be the diameter, which is well known to be two times the radius of the circle, so we can say that the circumference is just:

d\pi

So, solving for both the radius and the diameter gives us:

d\pi=8xy^2\pi\\ d=8xy^2\\ \\ 2\pi r=8xy^2\pi\\ r=4xy^2

So, the length of thes traight path that goes through the center of the guardain is just 8xy^2, and we can use the radius for the next part of the problem.

The area of a circle is \pi r^2, which means we can just plug in the radius and find our area:

A=\pi r^2 \implies \\ A=\pi (4xy^2)^2\implies \\ A= 16\pi x^2y^4

So, we have found our area(16 \pi x^2 y^4) and the problem is done.

6 0
3 years ago
Suppose we want to choose a value of x within 3 units of 11. [This means a value of x that is less than 3 units away from 11.] T
Dahasolnce [82]

Answer:

(a) [8, 14]

(b)  8 \leq x \leq 14

(c)See attachment

Step-by-step explanation:

We want to choose a value of x within 3 units of 11.

(a)Now, 11-3=8 and 11+3=14

The possible values of x ranges is in the closed interval [8,14]

(b) Since x is within 3 units of 11., we have:

|11-x|\leq3

Solving the absolute inequality

-3 \leq 11-x \leq 3\\$In $ -3 \leq 11-x\\ x \leq 11+3\\x \leq 14\\\\$In $ 11-x \leq 3\\ 11-3 \leq x\\8 \leq x\\$Therefore,an inequality that represents all values of x that meet this constraint is:$\\8 \leq x \leq 14

(c)To draw the number line, we use a closed dot since we have the less than or equal to sign.

5 0
3 years ago
Read 2 more answers
Let f(x) = Ax + B and g(x) = Cx + D where A, B, C, and D are non-zero constants. Use upper case letters for A, B, C, D and lower
Elodia [21]

Answer:

Let f(x) = Ax + B and g(x) = Cx + D where A, B, C, and D are non-zero constants. Use upper case letters for A, B, C, D and lower case letter for x in your answers below. (a) Find f(g(x)). f(g(x)) = A(Cx + D) + B (b) Find the slope of the function you found in part (a). slope = (c) Find the vertical intercept of the function you found in part (a). Do not write your answer as a point

6 0
3 years ago
Let set C = {1, 2, 3, 4, 5, 6, 7, 8} and set D = {2, 4, 6, 8}.
g100num [7]
<span>1. If it is intersection then it SHOULD be included in both the sets right? Now we know that odd numbers from 1-100 but the second set are multiples of 5 from 50-150! So we mainly need to look for common numbers which are ODD and are a MULTIPLE OF 5 BETWEEN 50 - 100!! So A={51,53,57,59,61......99} B={55,60,65,70.......95} [We stop till 100 because set A has no such element] So what is A ∩ B here? A ∩ B = {All odd numbers and multiples of 5 between 50 - 100}

</span>
6 0
3 years ago
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