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Aliun [14]
2 years ago
13

Hi pls help me thanksspls provide me with workings thankss :)​

Mathematics
1 answer:
melomori [17]2 years ago
5 0

Step-by-step explanation:

Happy New Year Everyone!!!

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Bogdan [553]

y-intercept for x = 0.

Substitute x = 0 to the equation of the function:

f(x)=-32(2)^{x-3}+3\\\\f(0)=-32(2)^{0-3}+3=-32(2)^{-3}+3=-32\cdot\dfrac{1}{2^3}+3=-32\cdot\dfrac{1}{8}+3\\\\=-4+3=-1\\\\Answer:\ \boxed{y-intercept=-1\to(0,\ -1)}

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3 years ago
What is the domain and range of each function graohed below?
andriy [413]
Domain is the x values you can use
range is the y values



a.
the domain
hmm, seems to be all real numbers except for at x=0, it gets really close tho
so D=(-∞,0)U(0,∞)

range is all real numbers except for y=0, it gets really close tho
R=(-∞,0)U(0,∞)



b.
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that empty circle means something like < or >
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3 years ago
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