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3 years ago

Who can help me with this?

Mathematics

2 answers:

Angelina_Jolie [31]3 years ago

8 0

Ask your older Brother or Sister to help you they could probably help you with it!

ipn [44]3 years ago

3 0

PROBLEM SOLVING:
19.) 4.4 meters
20.) 8.205 and 8.211
21.) 2,549
22.) see image attached to this answer.
23.) 2.36 rounded to the nearest hundredth is 2.4, 2.09 rounded to the nearest hundredth is 2.1 < 2.4 so 2.1 is closer to 0.
24.) 1/3
25.) Ruby started with $84.
Equation: m = (18 + 4 + 30) + 32

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Which system of equations has one solution? –5x – 10y = 24 5x 10y = 16 3x 4y = –7 –3x – 4y = 7 –12x 8y = 16 12x – 8y = 16 –2x 7y

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The system of equation that has one solution is: (d) –2x+ 7y = –5 and 2x +7y = –9

<h3>What are systems of equations?</h3>

This is a group of equations which may have none, one or more solutions.

From the list of given options, the system of equations that has one solution is:

–2x+ 7y = –5 and 2x +7y = –9

This is so because, the solution is (-1,-1)

However, the other systems have infinite many solutions

Read more about system of equations at:

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3 years ago

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4 years ago

A survey is to be conducted in which a random sample of residents in a certain city will be asked whether they favor or oppose t

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A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$p$ represent the real population proportion of interest

$\aht p$ represent the estimated proportion for the sample

n is the sample size required (variable of interest)

$z$ represent the critical value for the margin of error

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})$

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 90% of confidence, our significance level would be given by $\alpha=1-0.90=0.10$ and $\alpha/2 =0.05$ . And the critical value would be given by:

$z_{\alpha/2}=-1.64, z_{1-\alpha/2}=1.64$

The margin of error for the proportion interval is given by this formula:

$ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$ (a)

And on this case we have that $ME =\pm 0.05$ and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}$ (b)

We can assume that the estimates proportion is 0.5 since we don't have other info provided to assume a different value. And replacing into equation (b) the values from part a we got:

$n=\frac{0.5(1-0.5)}{(\frac{0.05}{1.64})^2}=268.96$

And rounded up we have that n=269

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